(x-4)² + (x-2)² = x²
(x² - 8x + 16 ) + (x² - 4x + 4) = x
2x² -12x + 20 = x
2x²-12x + 20 - x = 0
2x² - 13x + 20 = 0
(2x-5) (x-4) = 0
2x-5 = 0
2x = 5
x = ⁵/₂
x-4 = 0
x = 4
so x₁ = ⁵/₂ , and x₂ = 4
<h3>
Answer: 
</h3>
The -3 is not in the exponent
Explanation:
The parent function is
. Plugging in x = 0 leads to y = 1. So the point (0,1) is on the f(x) curve. Going from (0,1) to (0,-2) is a vertical shift of 3 units downward. To represent this shift, we tack on a "-3" at the end of the f(x) function.

You could look at other points as well, but I find working with x = 0 is easiest.
As a check, plugging x = 0 into g(x) leads to...

This confirms our answer.
[ Answer ]

[ Explanation ]
- System Of Equations

-----------------------------------

- Isolate x for x + x + 10 = 10: x = 0
For y = 10
Substitute x = 0
Y = 0 + 10
0 + 10 = 10
y = 10
X = 0
Y = 10
![\boxed{\bold{[] \ Eclipsed \ []}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cbold%7B%5B%5D%20%5C%20Eclipsed%20%5C%20%5B%5D%7D%7D)
Answer:
7.04, 7.134 ,7.2, 7.413
Step-by-step explanation: