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3 years ago

Are the lines 5x-5y=12 and x-y=-3 perpendicular or parallel

Mathematics

1 answer:

Goshia [24]3 years ago

3 0

Parallel both have slope 1

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Find the surface area of the right triangle prism(above) using the net (below)

kifflom [539]

Answer:

144

Step-by-step explanation:

2( 1/2 × 3 × 4 ) + ( 11 × 5) + ( 11 × 4 ) + ( 11 × 3)

= 12 + 55 + 44 + 33

= 144

7 0

2 years ago

6. Solve this inequality: j/4 -8 < 4.

Vaselesa [24]

Answer:

Step-by-step explanation:

Given

$\frac{j}{4}$ - 8 < 4 ( add 8 to both sides )

$\frac{j}{4}$ < 12

Multiply both sides by 4 to clear the fraction

j < 48 → D

6 0

3 years ago

Consider the quadratic function:<br> f(x) = x2 – 8x – 9

Bumek [7]

Solved in quadratic function
The answer :
X=(9,-1)

7 0

3 years ago

What is the solution to this equation?<br> 9x - 4(x - 2) = x + 20

ioda

9x - 4(x - 2) =x + 20

We move all terms to the left:

9x -4(x - 2) - (x + 20) = 0

Multiply

9x - 4x -(x + 20) + 8 = 0

We get rid of the parentheses.

9x - 4x - x - 20 + 8 = 0

We add all the numbers and all the variables.

4x - 12 = 0

We move all terms containing x to the left hand side, all other terms to the right hand side

4x=12
x = 12/4
x = 3

7 0

2 years ago

Ummm i don’t understand these I just started can someone help

bixtya [17]

so for question 2 find the area of the rectangle first:

$15 \times 19 = 285$

then you find the area of the triangles:

$15 \times 13 = 195 \\ 195 \div 2 = 97.5$

$15 \times 11 = 165 \\ 165 \div 2 = 82.5$

Add up all the answers:

$285 + 97.5 + 82.5 = 465$

and for question 3, part A, you just find the area of the 2 boxes and multiply:

$5 \times 5 = 25 \\ 25 \times 2 = 50$

$2 \times 5 = 10 \\ 10 \times 4 = 40$

$40 + 50 = 90$

so the surface area of the box is 90 square inches therefore the paint covered 90 square inches. For part B, just add up the length of the thick black lines:

$5 + 5 + 5 + 5 + 2 + 5 + 5 + 5 + 5 + 5 + 5 + 2 + 5 + 5 = 64$

How these helped have a good day

8 0

3 years ago