Answer:
We are given that the frame is 2 units wide, which means that we subtract the length of the outer frame by 2 units for each side:
7 - 2 -2 = 3
9 - 2 -2 = 5
Now, we have the length and width for the smaller rectangle, so we use the area formula (area = length*width) to get:
3*5 = 15
Step-by-step explanation:
Please support my answer.
We have to calculate the area of the rhombus if AE = 20 m and DE = 32 m.The diagonals DB = 2 * DE and AC = 2 * AE.
DB = 2 * 32 = 64 mAC = 2 * 20 = 40 mArea = d1 * d2 / 2 = DB * AC / 2 = 64 * 40 / 2 = 1,280 m²Answer: The area of the rhombus is B ) 1,280 m².
Answer:
80
Step-by-step explanation:
7-(5-3(2+6(2^2)))
When a question has multiple signs, the rule of BODMAS is used. That is, Bracket Of Division Multiplication Addition and Subtraction. The question above will therefore be solved in that order.
The first bracket, we have 2^2
That gives 4
Rewriting the question will give
7-(5-3(2+6(4)))
The question in the next bracket will follow
(2+6(4))
In this bracket too, we have the plus sign and the multiplication sign, so the multiplication will first be solved, them addition will follow.
(2+24)
(26)
Rewriting the question again, we have
7-(5-3(26))
And then, we have the last bracket
(5-3(26))
But we have both the Subtraction sign and the Multiplication sign in this bracket also, so the multiplication will first be solved, before the Subtraction.
(5-3(26))
(5-78)
(-73)
And lastly we have
7-(-73)
7+73
80
