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Snowcat [4.5K]
3 years ago
15

Which correctly describes a cross section of the cube below? Check all that apply.

Mathematics
1 answer:
mixer [17]3 years ago
6 0

Answer:

check the first one only

Step-by-step explanation:

in a cube, no matter which side it is, there will never be a rectangle, it will all be squares

not exactly good at drawing but I drew out what the description looks like and hope you can somehow understand it better!

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Plz someone help me.
satela [25.4K]
Hope this helps you! (and I'm right LOL)


5 0
3 years ago
Explain the steps to finding the vertex of g(x) = 3x2 + 12x + 15
RUDIKE [14]

Answer:

The vertex of this parabola, (-2, 3), can be found by completing the square.

Step-by-step explanation:

The goal is to express this parabola in its vertex form:

g(x) = a\, (x - h)^2 + k,

where a, h, and k are constants. Once these three constants were found, it can be concluded that the vertex of this parabola is at (h,\, k).

The vertex form can be expanded to obtain:

\begin{aligned}g(x)&= a\, (x - h)^2 + k \\ &= a\, \left(x^2 - 2\, x\, h + h^2\right) + k = a\, x^2 - 2\, a\, h\, x + \left(a\,h^2 + k\right)\end{aligned}.

Compare that expression with the given equation of this parabola. The constant term, the coefficient for x, and the coefficient for x^2 should all match accordingly. That is:

\left\lbrace\begin{aligned}& a = 3 \\ & -2\,a\, h = 12 \\& a\, h^2 + k = 15\end{aligned}\right..

The first equation implies that a is equal to 3. Hence, replace the "a\!" in the second equation with 3\! to eliminate \! a:

(-2\times 3)\, h = 12.

h = -2.

Similarly, replace the "a" and the "h" in the third equation with 3 and (-2), respectively:

3 \times (-2)^2 + k = 15.

k = 3.

Therefore, g(x) = 3\, x^2 + 12\, x + 15 would be equivalent to g(x) = 3\, (x - (-2))^2 + 3. The vertex of this parabola would thus be:

\begin{aligned}&(-2, \, 3)\\ &\phantom{(}\uparrow \phantom{,\,} \uparrow \phantom{)} \\ &\phantom{(}\; h \phantom{,\,} \;\;k\end{aligned}.

8 0
3 years ago
Amuseumcharges forgeneraladmission and exhibitions. Admission and 3 exhibitionscosts $45. Admission and 5 exhibitionscosts $65.
leonid [27]

Answer:

The price of the admission is 15.

Step-by-step explanation:

From the information given, you can write the following equations:

a+3e=45 (1)

a+5e=65 (2), where:

a is the admission cost

e is the exhibition cost

First, you can solve for a in (1):

a=45-3e (3)

Second, you can replace (3) in (2):

45-3e+5e=65

45+2e=65

2e=65-45

2e=20

e=20/2

e=10

Finally, you can replace the value of e in (3):

a=45-3e

a=45-3(10)

a=45-30

a=15

According to this, the price of the admission is 15.

3 0
3 years ago
Solve for y, then find the value of y when given x= -2
8090 [49]
Your answer will be c.


7 0
3 years ago
Erin has scanned a 4 × 5-inch postcard, and she wants to reduce it to make a graphic for her Web site. She will use a scale fact
Rasek [7]
Just multiply both dimensions by 2 to make it into centimeters.

Therefore,

4*2 x 5*2 (in inches) will be:

8cm x 10cm (in centimeters)

We conclude that the dimensions of her postcard into a graphic on her web page will be 8x10 in centimeter units. 

I hope my answer has come to your help. Thank you for posting your question here in Brainly.
6 0
3 years ago
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