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3 years ago

Find the value of a°

Mathematics

2 answers:

Misha Larkins [42]3 years ago

7 0

Answer:

If two vectors are parallel, applying the same side interior angles theorem:

=> 80 + a + 59 = 180

=> a = 180 - 80 - 59 = 41 deg

Hope this helps!

Goshia [24]3 years ago

4 0

Or you could apply alternate angle theorem

Alternate angles make a "z" shape. Alternate angles are equal

So now that we know the third side of the triangle is equal to 59, we do 180=a+59+80

Move fifty nine and eighty to the other side as negative numbers

a=180-59-80

So, a is equal, to 41 :))

You might be interested in

Can someone with knowledge see what I did wrong on number 4 also see if number 3 is right

Yakvenalex [24]

Answer:

#4. m=0;

#3. m = $\frac{-1}{2}$

Step-by-step explanation:

It seems right.

#4.

Maybe your teacher wants you to write m=0; because when a fraction has a numerator equal to zero then the fraction is zero.

#3.

Maybe your teachers want you to simplify the fraction and write m = $\frac{-1}{2}$

7 0

3 years ago

Read 2 more answers

George and Paula are running around a circular track. George starts at the westernmost point of the track, and Paula starts at t

arsen [322]

Answer:

George is 43.20 ft East of his starting point.

Step-by-step explanation:

Let Paula's speed be x ft/s

George's speed = 9 ft/s

Note that speed = (distance)/(time)

Distance = (speed) × (time)

George takes 50 s to run a lap of the track at a speed of y ft/s

Meaning that the length of the circular track = y × 50 = 50y ft

George and Paula meet 14 seconds after the start of the run.

Distance covered by George in 14 seconds = 9 × 14 = 126 ft

Distance covered by Paula in 14 seconds = y × 14 = 14y ft

But the sum of the distance covered by both runners in the 14 s before they first meet each other is equal to the length of the circular track

That is,

126 + 14y = 50y

50y - 14y = 126

36y = 126

y = (126/36) = 3.5 ft/s.

Hence, Paula's speed = 3.5 ft/s

Length of the circular track = 50y = 50 × 3.5 = 175 ft

So, in 4 minutes (240 s), with George running at 9 ft/s, he would have ran a total distance of

9 × 240 = 2160 ft.

2160 ft around a circular track of length 175 ft, means that George would have ran a total number of laps (2160/175) = 12.343 laps.

Breaking this into 12 laps and 0.343 of a lap from the starting point. 0.343 of a lap = 0.343 × 175 = 60 ft

So, 60 ft along a circular track subtends an angle θ at the centre of the circle.

Length of an arc = (θ/360°) × 2πr

2πr = total length of the circular track = 175

r = (175/2π) = 27.85 ft

Length of an arc = (θ/360) × 2πr

60 = (θ/360°) × 175

(θ/360°) = (60/175) = 0.343

θ = 0.343 × 360° = 123.45°

The image of this incomplete lap is shown in the attached image,

The distance of George from his starting point along the centre of the circular track = (r + a)

But, a can be obtained using trigonometric relations.

Cos 56.55° = (a/r) = (a/27.85)

a = 27.85 cos 56.55° = 15.35 ft

r + a = 27.85 + 15.35 = 43.20 ft.

Hence, George is 43.20 ft East of his starting point.

Hope this Helps!!!

6 0

3 years ago

How many 0 are in one million

Shalnov [3]

Answer:

Step-by-step explanation:

4 0

3 years ago

Which answer describes the simpler problems that could be used to solve this story problem?

ICE Princess25 [194]

D. cause you gotta isolate your variables (the cereal boxes) then get rid of the coefficent (2)

8 0

3 years ago

You and your friend mix water and cirtic acid. You add 3 cups of citrtic acid for every 16 cups of water Your friend adds 2 cups

Vlad [161]

Answer:

A's mixture is more acidic.

Step-by-step explanation:

Given:

Two friends mix water and citric acid.

One (Let A) add 3 cups of citric acid for every 16 cups of water and another (Let B)adds 2 cups of citric acid for every 12 cups of water.

Now, we have to find that whose mixture is more acidic means:-

Solution:

A add 3 cups of citric acid for every 16 cups of water, the ratio = $\frac{3}{16}$

B adds 2 cups of citric acid for every 12 cups of water = $\frac{2}{12}$

Now, to find that who mix more citric acid in the mixture, firstly we will equalize the denominator of both fraction by taking LCM so that can be compare easily.

LCM of 16 and 12:- 48

16 - 16, 32, 48, 64, 80, 96....

12 - 12, 24, 36, 48, 60, 72.......

For friend A - $\frac{3\times3}{16\times3} =\frac{9}{48}$

For friend B - $\frac{2\times4}{12\times4} =\frac{8}{48}$

We found that in terms of 48 cups of water, friend A mixes 9 cups of acid while friend B mixes 8 cups of acid, means A is adding more acid than B and hence friend A's mixture is more acidic.

4 0

3 years ago