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3 years ago

A radio host plans to play one song from each of the three CDs he has by a single artist. The first

Mathematics

1 answer:

Orlov [11]3 years ago

4 0

Answer:

2184 ways

Step-by-step explanation:

We need to choose exactly one song from each CD, so the number of possible ways to choose a song from a CD is the number of songs in that CD.

The first song is from a CD with 12 songs, so there are 12 possibilities of choosing a song.

The second song is from a CD with 14 songs, so there are 14 possibilities of choosing a song.

The third song is from a CD with 13 songs, so there are 13 possibilities of choosing a song.

Now, to find the number of possible ways to play these songs, we just need to multiply the number of possibilities for each song:

Number of possible ways = 12 * 14 * 13 = 2184 ways

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PLEASEEEE SOMEONE HELP ME WITH THIS ITS DUE IN A COUPLE HOURS!!!!! FOR trigonometry

Natasha2012 [34]

Answer:

4/7

Step-by-step explanation:

Tan= Opposite/Adjacent

Tan<f = 4/7

8 0

3 years ago

4w^2+49=-28w solve for w<br><br> plz answer

boyakko [2]

Move all terms to one side

4w^2 + 49 + 28w = 0

Rewrite 4w^2 + 49 + 28w in the form a^2 + 2ab + b^2, where a = 2w and b = 7

(2w)^2 + 2(2w)(7) + 7^2 = 0

Use the Square of Sum: (a + b)^2 = a^2 + 2ab + b^2

(2w + 7)^2 = 0

Take the square root of both sides

3w + 7 = 0

Subtract 7 from both sides

2w = -7

Divide both sides by 2

3 0

3 years ago

A vehicle arriving at an intersection can turn right, turn left, or continue straight ahead. The experiment consists of observin

Temka [501]

Answer:

a) Sample space (S) = {TR, TL, Cs}

b) Pr(Vehicle Turns) = 2/3.

Step-by-step explanation:

a) By sample space (S) we mean the list all possible outcome of an event. From the illustration in the question, only three (3) outcome is possible:

i) Vehicle Turn Right (TR)

ii) Vehicle Turn Left (TL)

iii) Continue Straight ahead (Cs)

And since the experiment consists of observing the movement of a single vehicle through the intersection, then, the sample space (S) is:

==> {TR, TL, Cs}

b) Since we are assuming that all sample points are equally likely, it imply that they have equal probability of occurring. And by probability:

Pr(TR) = 1/3

Pr(TL) = 1/3

Pr(Cs) = 1/3

Meanwhile, the question wants us to find the probability that the vehicle turns. This means, the vehicle turning either right or left. Thus;

Pr(vehicle turns) = Pr(TR) or Pr(TL) = Pr(TR) + Pr(TL)

Pr(vehicle turns) = (1/3) + (1/3) = 2/3

4 0

3 years ago

Plz hurry!!!! thank you!!!!

tatyana61 [14]

Step-by-step explanation:

Since SP=TR, the differnce of PR and ST 24-15 divided by 2 is the length of PD (4.5)

Try to understand the rest from the attached picture

3 0

3 years ago

(7t-2)-(-3t+1)=-3(1-3t)

Aleksandr-060686 [28]

First you need to multiple minus in second bracket, also in other side you need to multiple - 3 in bracket

$7t - 2 + 3t - 1 = - 3 + 9t \\ \\ 10t - 3 = - 3 + 9t \\ 10t - 9t = - 3 + 3 \\ t = 0$
Final answer is 0

5 0

3 years ago