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3 years ago

Someone please help with this question

Mathematics

2 answers:

IRINA_888 [86]3 years ago

7 0

Answer:

A=230 cm2

Step-by-step explanation:

A1= L x W HEIGHT OF TRIANGLE=16-7=9

A1=20 x 7

A1=140 cm2

A2=1/2 x B x H

A2=1/2 x 20 x 9

A2=90 CM 2

Korolek [52]3 years ago

6 0

Answer:

230

Step-by-step explanation:

9 times 20 = 180

divide by 2 = 90

7 times 20 = 140

140 + 90 = 230

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Free_Kalibri [48]

Answer:

The answer is C.-216

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A parabola can be drawn given a focus of

Volgvan

Answer:

$y=-\frac{1}{4}(x-2)^{2}+9$

Step-by-step explanation:

Any point on a given parabola is equidistant from focus and directrix.

Given:

Focus of the parabola is at $(2,8)$ .

Directrix of the parabola is $y=10$ .

Let $(x,y)$ be any point on the parabola. Then, from the definition of a parabola,

Distance of $(x,y)$ from focus = Distance of $(x,y)$ from directrix.

Therefore,

$\sqrt{(x-2)^{2}+(y-8)^{2}}=|y-10|$

Squaring both sides, we get

$(x-2)^{2}+(y-8)^{2}=(y-10)^{2}\\(x-2)^{2}=(y-10)^{2}-(y-8)^{2}\\(x-2)^{2}=(y-10+y-8)(y-10-(y-8))...............[\because a^{2}-b^{2}=(a+b)(a-b)]\\(x-2)^{2}=(2y-18)(y-10-y+8)\\(x-2)^{2}=2(y-9)(-2)\\(x-2)^{2}=-4(y-9)\\y-9=-\frac{1}{4}(x-2)^{2}\\y=-\frac{1}{4}(x-2)^{2}+9$

Hence, the equation of the parabola is $y=-\frac{1}{4}(x-2)^{2}+9$ .

4 0

3 years ago

The dimensions for a rectangular prism are x + 2 for the length, x + 3 for the width, and x for the height. What is the volume o

Jlenok [28]

V = lwh

V = (x + 2)(x + 3)(x)

V = (x)(x^2 + 3x + 2x + 6)

V = (x^3 + 3x^2 + 2x^2 + 6x)

V = x^3 + 5x^2 + 6x

All you do is foil the dimensions together and then combine like terms. Hope this helps!

7 0

3 years ago

LCM of 14 and 49? Evaluate plz

ICE Princess25 [194]

Answer:

Step-by-step explanation:

Express the numbers in terms of the product of their prime factors

14 = 2 × 7

49 = 7 × 7 = 7²

Choose the factors which occur most often between the 2 numbers

LCM = 2 × 7² = 2 × 49 = 98

5 0

3 years ago

36 fifth graders are on a team with the same number on students on each team, if there are more then then 1 but less then 20 tea

frosja888 [35]

Depending on the number of teams, the possible numbers of students per team are in the set:

{2, 3, 4, 6, 9, 12, 18}

<h3>How many students can be on each team?</h3>

We know that there are 36 students divided equally into N teams.

Such that the number of teams is larger than 1 and smaller than 20.

Then we could have 2 teams, such that the number of students in each team is given by the quotient between the total number of students and the number of teams.

36/2 = 18

There are 18 students in each team.

Notice that the numbers of teams can only be factors of 36, where:

36 = 6*6 = 2*2*3*3

So the factors are:

2, 3, 2*3, 3*3, etc...

If there are 3 teams we have:

36/3 = 12 students per team.

If there are 6 teams we have:

36/6 = 6 students per team.

if there are 9 teams:

36/9 = 4 students per team.

If there are 12 teams:

36/12 = 3 students per team.

If there are 18 teams:

36/18 = 2 students per team.

These are all the possibilities.

If you want to learn more about factors:

brainly.com/question/219464

#SPJ1

7 0

2 years ago