Step-by-step explanation:
$2.00x-($.10x)=3+x
the x would stand for cups and since you already get 3 more cups in a day than before then you would put 3+x_how many cups you sell. the $2.00 is for how much money each up is. and the -$.10 is subtracting 10 cents for each cup you sell.
I dont know if this is correct but this is how I would make my equation
Answer:

Step-by-step explanation:
First, we need to find the sequence associated to the summation. As you can see the sum only takes odd numbers into account. Hence the sequence it is defined by:

Where:

Now, we only need to find the limits of the summation:
Evaluating n=1

Evaluating n=50

Therefore the summation can be written as:

Answer: 49 people
Step-by-step explanation:
First you need to separate the people that read both from the people that read the daily news. Do this by subtracting 171 - 40 = 131.
Now you can subtract the total amount of people that only read the Daily Mews from the total amount of people polled (198-131=67)
From here you need to subtract the amount of people that read neither from the remaining total. (67-18=49)
this is where you get the 49 people out of 198 that read the Sun Gazette
Answer:
(-2,5)
Step-by-step explanation:
Answer:A)35choices
B)475,020choices
C)132choices
D)0.000278
E)0.000166
Step-by-step explanation:
Given 7poultry items represented by 7p
10 red meat items=10R
12 vegetarian items=12V
@
A)there are 7combination 3ways of selecting 3out of 7 poultry items
From the formula nCr=n!/(n-r)!r!
7C3=7!/(7-3)!3!=7!/4!×3!=35choices
b)total items available=7p+10R+12V(denotation explained above)=29items
Choosing 6items implies
29C6=29!/(29-6)!×6!
29!/23!×6!=475,020 ways
C)7C2+10C2+12C2
7!/5!2!+10!/8!2!+12!/10!2!
21+45+66=132 choices
D) probability (choosing 2items from each class)=
7C2+10C2+12C2/29C6
Where 29C6 represent total probable.
21+45+66/29!/23!6!
=132/475020=0.000278choices
E)for meats to be in the majority on a 6choices selection impliee that vegetarian items will be
0,1 or2i.e combination of vegetarian and meat will be(0,6)or(1,5)or(2,4) .
Prob(0veg)+prob(1veg item) or prob(2veg items)
12C0+12C1+12C2/29C6
=1+12+66/475,020
=0.000166