The function which represents the taxi fare in terms of distance d in meter is f(d) = 3.50 ×
+ 40 .
According to the question,
For first 500 meters cost is 40.00 and For each additional 300 meters cost is 3.50 .
Let, the total distance of taxi ride = d meters
Now, representing the equation of taxi fare in terms of distance when distance is less than 500
taxi fare = 3.50 ×
+ 40
∴ f(d) = 3.50 ×
+ 40
To know more about functions refer below link: brainly.com/question/12431044
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Answer:
14 year old you tuber
Step-by-step explanation:
=)
1) Tanθ= opposite/adjacent
θ=Tan-1(9/7)
θ=52.125 = 52 degrees
2) Cosθ= adjacent/hypothesis
θ=Cos-1(5/12)
θ=65.376 = 65 degrees
Here you go, i added a bit of explanation as to why i used the numbers to help you understand the method :)
They complete a 900-mile distance with their combined speed of (300+250=550) mph
Therefore, they meet after 900m/550mph=18/11h=1.6364h