1/49=x^2 where x is the side of the square
1/49=(1/7)^2, so the side length of the square is 1/7
P(at least 2 students have the same birthday)= 1- P(no 2 students have the same birthday)
Because P(A)=1-P(A'), where A is an event, and A' the complement of that event.
P(no 2 students have the same birthday)=

think of the problem as follows. We have an urn of balls, numbered from 1 to 365 (the number of the days of the year.
What is the probability of picking 56 different numbered balls, with replacements?
The first one can be any of the 365
the second any of 364 (since one selection has already been made)
the third any of the 363
.
.
and so on
the 56th selection is one of 310 left
Answer:
The opposite of a number is the number on the other side of 0 number line, and the same distance from 0.
A) 8
B)0
C)-4
F(3)=2*3²+3=18=3=21
C is the answer
This is an impossible equation.
If you have something and you add 3 to it, how can the result be the same as the original?