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2 years ago

The five new teachers at a school were surveyed. Is this sample of teachers at the school likely to be biased?

Mathematics

2 answers:

nordsb [41]2 years ago

8 0

Answer:

yes because since they are new they are all going to have a different opinion on the school than other teachers thats been there for years

hope this helps

have a good day :)

Step-by-step explanation:

Alona [7]2 years ago

6 0

Yes, it would likely be biased because they might be like an advertisement since they weren't teaching for years at this school.

If this helps, please mark me brainliest!

Have an amazing day!

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Citrus2011 [14]

Ans. 1 Angle E and angle F are corresponding angles.

Solution 2.

So,

angle E = angle F

=> x + 20 = 5x - 20

=> x + 20 + 20 = 5x

=> x + 40 = 5x

=> 40 = 5x - x

=> 40 = 4x

=> 40/4 = x

=> 10 = x

Solution 3.

E = x + 20

=> E = 10 + 20

=> E = 30

F = 5x - 20

=> F = 5(10) - 20

=> F = 50 - 20

=> F = 30

Again justified that they are equal ( besides answer 1).

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3 years ago

Use the Taylor series you just found for sinc(x) to find the Taylor series for f(x) = (integral from 0 to x) of sinc(t)dt based

Marina CMI [18]

In this question (brainly.com/question/12792658) I derived the Taylor series for $\mathrm{sinc}\,x$ about $x=0$ :

$\mathrm{sinc}\,x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}$

Then the Taylor series for

$f(x)=\displaystyle\int_0^x\mathrm{sinc}\,t\,\mathrm dt$

is obtained by integrating the series above:

$f(x)=\displaystyle\int\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}\,\mathrm dx=C+\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

We have $f(0)=0$ , so $C=0$ and so

$f(x)=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

which converges by the ratio test if the following limit is less than 1:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+3}}{(2n+3)^2(2n+2)!}}{\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)^2(2n)!}{(2n+3)^2(2n+2)!}$

Like in the linked problem, the limit is 0 so the series for $f(x)$ converges everywhere.

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2 years ago

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stepladder [879]

Answer:

f = 27

Step-by-step explanation:

11 = f - 16

Add 16 to both sides.

11 + 16 = f - 16 + 16

27 = f

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3 years ago

Read 2 more answers

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Zigmanuir [339]

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