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3 years ago

Name:

Mathematics

1 answer:

lubasha [3.4K]3 years ago

4 0

Answer:

3,225

Step-by-step explanation:

principal times interest time rate

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just olya [345]

Answer:

42 degrees

Step-by-step explanation:

the 138 goes on the opposite side aswell.

it adds up to 180 total so 180-132 = 42

6 0

2 years ago

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Need help solving problem

Andreas93 [3]

I can not see the picture

4 0

3 years ago

Find the missing values of the variables. The diagram is not to scale. (Image attached below)thank you ! :)

aniked [119]

Answer:

$\begin{gathered} x=\text{ 99}\degree \\ y\text{ = 64}\degree \end{gathered}$

Explanation:

Here, we want to get the value of x and y

From the given image, the angle y and 116 lie on a straight line

The sum of the angles on a straight line is 180 degrees

Thus:

$\begin{gathered} 116\text{ + y = 180} \\ y\text{ =180-116} \\ y\text{ = 64}\degree \end{gathered}$

The sum of the internal angles of a polygon can be calculated by the formula:

$180(n-2)$

where n is the number of sides the polygon has

In the case of the given question, n is 4

Substituting the value of n, we have it that:

$180(4-2)\text{ = 360 degrees}$

To get the value of x:

$\begin{gathered} x\text{ + y + 125 + 72 = 360} \\ But\text{ from above , y = 64}\degree \\ Substituting\text{ this:} \\ x\text{ + 64 + 125 + 72 = 360} \\ x\text{ = 360-125-64-72} \\ x\text{ = 99 } \end{gathered}$

4 0

1 year ago

Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

5 0

3 years ago

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WARRIOR [948]

$28.3 each I know this because you subtract 35 from 130 and you get 85. Then you do 85 divided by 3 and get 28.3

4 0

3 years ago

Read 2 more answers