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Yanka [14]
4 years ago
7

Find the missing side

Mathematics
1 answer:
enot [183]4 years ago
8 0

Answer:

its E 21

Step-by-step explanation:

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Let μ denote the true average reaction time to a certain stimulus. For a z test of H0: μ = 5 versus Ha: μ > 5, determine the
noname [10]

Answer: 0.0708

Step-by-step explanation:

Let μ denote the true average reaction time to a certain stimulus.

To determine : The P-value for a z test of H0: μ = 5 versus Ha: μ > 5.

In the given set of hypothesis , the alternative hypothesis is right -tailed , so the test is a right tailed test .

Given test statistic : a) z= 1.47

Now, the p-value for the right tailed test :

P(z>1.47)=1-P(z\leq1.47)\ \ [\because P(Z>z)=1-P(Z\leq z)]

=1-0.9292=0.0708

[Using the p-value table for z]

Hence, the required P-value = 0.0708

5 0
3 years ago
Which methods can you use to solve this problem: <br> X^2 -47=0
ivann1987 [24]
This is the awnser too this one

5 0
3 years ago
Can someone hep explain this plese
enyata [817]

Answer:

multiply the 3 and the 2= 6

Step-by-step explanation:

6 is the answer

3 0
3 years ago
A loan processing office receives 4 loan requests every hour. The office has 2 departments. It takes the first department on ave
jenyasd209 [6]

Answer:

On average how many requests are in the first department (including those who are waiting) is 1.32.

Step-by-step explanation:

In this case, use the Little's law of queuing theory.

The Little's law states that the average number of customers in a fixed system (L) is equal to the average effective arrival rate (λ) multiplied by the average time a customer spends in the system (W).

The number of requests per hour in the 1st department is, λ₁ = 4.

It is provided that 20% are rejected directly by the 1st department without going into the 2nd department.

Then the number of requests per hour is, λ₂ = 4\times 80\%=4\times0.80=3.2

The average time a customer spends in the 1st department,

W₁ = 20 minutes = 0.33 hours.

The average time a customer spends in the 1st department,

W₂ = 60 minutes = 1 hour

On average how many requests are in the first department (including those who are waiting) is:

<em>L</em> = λ₁ × W₁

  = 4 × 0.33

  = 1.32

Thus, on average how many requests are in the first department (including those who are waiting) is 1.32.

6 0
4 years ago
Help needed here. So Please help.
earnstyle [38]

Answer:

I notice in the compensation strategy it's much simpler than basic subtraction.

Step-by-step explanation:

Just say that ;)

5 0
3 years ago
Read 2 more answers
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