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Zarrin [17]
2 years ago
10

Prove that triangle ABD is congruent to triangle CBD.

Mathematics
1 answer:
Ede4ka [16]2 years ago
8 0

Answer:

AB=AC, BD is shared side, angle 1 and angle 2 are equal as BD bisects angle ABC

So we have two sides and included angle equal.

  • <em>If two sides and the included angle of one triangle are equal to the corresponding sides and angle of another triangle, the triangles are congruent.</em>

According to the rule above we can say triangles ΔABD ≅ ΔCBD

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Step-by-step explanation:


6 0
3 years ago
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Nina [5.8K]

Answer:

<em>5</em><em> players participated in the tournament.</em>

Step-by-step explanation:

In a small chess tournament, 20 matches were played.

Let us assume that n number of players participated in the tournament

As in each game 2 players play, so the number of ways they can play is,

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But it is given to be 20, so

\Rightarrow \ 2\times ^nC_2=20

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\Rightarrow \dfrac{n!}{2!(n-2)!}=10

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Therefore, 5 players participated in the tournament.

5 0
2 years ago
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parallelogram ABCD has vertices A(-2,-51/2), B(-4,-51/2), C(-3,-2), and D(-1,-2). find the vertices of parallelogram A'B'C'D' af
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On a coordinate plane, any movement up and down is on the y-axis. So if your parallelogram is moving down 2.5 units, then the y-values of each vertice will go down by 2.5:
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Area = Length * Width

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3 years ago
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