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enyata [817]
3 years ago
9

By what percent will a fraction decrease if its numerator is decreased by 50% and its denominator is decreased by 25%?

Mathematics
2 answers:
LuckyWell [14K]3 years ago
6 0
Let N be the numerator, D be the denominator 
\frac{N}{D}

if its numerator is decreased by 50%
N - \frac{50}{100}N ==> (this will be the numerator part)

if its denominator is decreased by 25%
D - \frac{25}{100}D ==> (this will be the denominator part)

I try to separate them out, so it's easier to see the problem.

N - \frac{50}{100}N = \frac{100N}{100} - \frac{50N}{100} = \frac{50N}{100}

D - \frac{25}{100}D = \frac{100D}{100} - \frac{25D}{100} = \frac{75D}{100}

\frac{\frac{50N}{100}}{\frac{75D}{100}} = \frac{50N}{100} * \frac{100}{75D}

\frac{50N}{75D} =  \frac{2}{3}(\frac{N}{D}) by this, you can understand that 
\frac{2}{3}(\frac{N}{D}) as 66.6% of N/D because 2/3 is 0.666666.... The answer should be 66.7% if you round them up. 

il63 [147K]3 years ago
3 0
The answer is 66.6666%
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Answer:

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Solving for Part A.

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Solving for Part D.

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