Answer:
Area of the given figure is 51.5 square units.
Step-by-step explanation:
Area of rectangle OCBH = Length × width
= 11 × 8
= 88 square units
Area of trapezoid OGEF = 
= 
= 
= 18 units²
Area of trapezoid GCDE = 
= 
= 13.5 units²
Area of triangle AFH = 
= 
= 5 units²
Area of polygon ABCDEF = Area of rectangle CBHO - (Area of trapezoid OGEF + Area of trapezoid GCDE + Area of triangle AFH)
= 88 - (18 + 13.5 + 5)
= 88 - 36.5
= 51.5 units²
Therefore, area of the given polygon is 51.5 units²
To draw line HI perpendicular to JK we need to follow the given steps:
Place your compass on the given point (point H). Draw an arc across the line on each side of the given point. Do not adjust the compass width when drawing the second arc.
From each arc on the line, draw another arc on the opposite side of the line from the given point (H). The two new arcs will intersect.
Use your ruler to join the given point (H) to the point where the arcs intersect (I).
HI is perpendicular to JK.
What is perpendicular?
Two distinct lines intersecting each other at 90°, or a right angle, are called perpendicular lines.
Properties of Perpendicular Lines
- These lines always intersect at right angles.
- If two lines are perpendicular to the same line, they are parallel to each other and will never intersect.
- Adjacent sides of a square and a rectangle are always perpendicular to each other.
- The sides of the right-angled triangle enclosing the right angle are perpendicular to each other.
To learn more about perpendicular lines,
brainly.com/question/1202004
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1/
V=44.312 in^3
2/
V=42.453 in^3
3/
V=75.36 in^3
4/
V=696.557 in^3
5/
V=671.175 in^3. Hope it help!
