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hram777 [196]
3 years ago
15

B(n)= -1(2)^n1 what is the 5th term in the sequence?

Mathematics
1 answer:
DanielleElmas [232]3 years ago
3 0
You just have to plug in 5 for n.
-1(2)^5(1)
-2^5(1)
-32(1)
-32 is the 5th term of the sequence.
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Step-by-step explanation:

Previous concepts

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The Cohen's D is given by this formula:

D = \frac{\bar X_A -\bar X_B}{s_p}

Where s_p represent the deviation pooled and we know from the problem that:

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