The minimum distance will be along a perpendicular line to the river that passes through the point (7,5)
4x+3y=12
3y=-4x+12
y=-4x/3+12/3
So a line perpendicular to the bank will be:
y=3x/4+b, and we need it to pass through (7,5) so
5=3(7)/4+b
5=21/4+b
20/4-21/4=b
-1/4=b so the perpendicular line is:
y=3x/4-1/4
So now we want to know the point where this perpendicular line meets with the river bank. When it does y=y so we can say:
(3x-1)/4=(-4x+12)/3 cross multiply
3(3x-1)=4(-4x+12)
9x-3=-16x+48
25x=51
x=51/25
x=2.04
y=(3x-1)/4
y=(3*2.04-1)/4
y=1.28
So now that we know the point on the river that is closest to Avery we can calculate his distance from that point...
d^2=(x2-x1)^2+(y2-y1)^2
d^2=(7-2.04)^2+(5-1.28)^2
d^2=38.44
d=√38.44
d=6.2 units
Since he can run at 10 uph...
t=d/v
t=6.2/10
t=0.62 hours (37 min 12 sec)
So it will take him 0.62 hours or 37 minutes and 12 seconds for him to reach the river.
Answer:
d
Step-by-step explanation:
BC supplementary means they add up to 180 and answer d adds up to 180
Answer:
x = 10
Step-by-step explanation:
Since both equations give y in terms of x, equate the right sides
3x - 28 = - 2x + 22 ( add 2x to both sides )
5x - 28 = 22 ( add 28 to both sides )
5x = 50 ( divide both sides by 5 )
x = 10
Answer: 1.645
Step-by-step explanation:
Given : The quality control manager of a soda manufacturing company wishes to use a significant level of 0.05 to test whether the variabilities in the amount of soda in the company's 16 OZ bottles is more than the variabilities in the company's 12 OZ bottles.
Let 
represents the variance for 16 OZ bottles and 
represents the variance for 12 OZ bottles.
The Null and Alternative Hypothesis will be :-
, since alternative hypothesis is left-tailed , then the test is left-tailed test.
By using the standard normal distribution table for z, the critical value for this hypothesis:-
Answer:
2/6
Step-by-step explanation:
1/3
Write an equivalent fraction by multiplying
1/3 * 2/2
2/6
I hope this was useful!
