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fgiga [73]
3 years ago
12

3x + 2y = 8 x + 3y = -2

Mathematics
1 answer:
stiks02 [169]3 years ago
5 0

Answer:

what is your question exactly?

Step-by-/step explanation:

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Find equivalent ways to rewrite the expression 6a^8÷3a^4​
solong [7]

Answer:

6a^8/3a^4= (6/3)= 2

a^8/a^4= a^4

2a^4

(6/3)(a^8/a^4)= 2a^4

(6/3)(a^(8-4))= 2a^4

Step-by-step explanation:

5 0
3 years ago
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When each side of an equation has been simplified, equations that have BLANK coefficients and BLANK constants on each side have
kobusy [5.1K]

Answer:

The answer is below

Step-by-step explanation:

An equation shows the relationship between two or more variables. An equation is a statement that shows the equality between expressions. An equation with infinitely many solution is when all numbers are solutions, that is there is no one solution. Example is: x + 3 = x + 3.

When each side of an equation has been simplified, equations that have the same coefficients and the same constants on each side have infinitely many solutions

7 0
3 years ago
The high temperature on Monday in Alaska was -2 degrees. Tuesday's high temperature was 3 degrees lower than Monday's. What was
oee [108]

Answer:

The answer is B) -5

Step-by-step explanation:

It is -5 because if you take monday's temperature and subtract it by tuesday's temperature. You get -5

-2-3=-5

3 0
3 years ago
Antonio invests 3000 at .10 interest compounded semianually for 12 years. Use the compound interest formula to calculate the com
marissa [1.9K]

Answer:

A=9675.299

Step-by-step explanation:

A=p(1+r)^t

A compound amount

P is the principle amount invested

r : rate ( semiannually is 0.5 )

t=years ( semiannually 12*2=24)

A=3000(1+0.10/2)^24

A=9675.299

8 0
3 years ago
Random samples of size 81 are taken from an infinite population whose mean and standard deviation are 200 and 18, respectively.
TiliK225 [7]

Answer:

d. 200 and 2

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

Mean = 200

Standard deviation = 18

Sample size: 81

Standard error: s = \frac{18}{\sqrt{81}} = 2

So the correct answer is:

d. 200 and 2

7 0
3 years ago
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