Answer:
6+4x-3z
Step-by-step explanation:
<u>-2</u>+6x+z-2x<u>+8</u>-4z
6<u>+6x</u>+z<u>-2x</u>-4z
6+4x<u>+z-4z</u>
6+4x-3z
Yes it is. In order for something to be a function, no X values can be the same, which is the case here.
Answer:
me
Step-by-step explanation:
pleas i'm begging you
Answer:
Correct answer: x₁ = 1 / √3 = √3 / 3 or x₂ = - 1 / √3 = - √3 / 3
Step-by-step explanation:
Given:
3 x⁴ + 14 x² - 5 = 0 biquadratic equation
this equation is solved by a shift x² = t and get:
3 t² + 14 t - 5 = 0
t₁₂ = (-14 ± √14² - 4 · 3 · 5) / 2 · 3 = (-14 ± √196 + 60) / 6
t₁₂ = (-14 ± √256) / 6 = (-14 ± 16) / 6
t₁ = -5 or t₂ = 1 / 3
the solution t₁ = -5 is not accepted because it cannot be x² = -5
we accepted t₂ = 1 / 3
x² = 1 / 3 ⇒
x₁ = 1 / √3 = √3 / 3 or x₂ = - 1 / √3 = - √3 / 3
God is with you!!!
