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3 years ago

I don’t need you to explain just answer.

Mathematics

1 answer:

victus00 [196]3 years ago

8 0

Answer: The answer is (x-5)^2

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Match each expression in the left column with the correct product in the right column.

lesya692 [45]

Answer:

-6

-6i

Step-by-step explanation:

1) √4 . √-3 . √-3

$\sqrt{4} = 2$

$\sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2$

$\sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 =$ -6

2) √-4 . √-3 . √-3

$\sqrt{-4} = 2i$ .

Therefore, $\sqrt{-4} . \sqrt{-3} . \sqrt{-3} = 2. \sqrt{-1} \times -3 = 2i \times (-3) =$ - 6i

3) √4 . √3 . √-3

$\sqrt{4} = 2$

$\sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1}$

$\implies 2 \times 3i =$ 6i

4) √4 . √3 . √3

$\sqrt{4} = 2$

$\sqrt{3} . \sqrt{3} = (\sqrt{3})^2 = 3$

Therefore, √4 . √3 . √3 = 2 . 3 = 6

5 0

3 years ago

Write 61/4℅ as a decimal

marta [7]

61/4 % converted into a decimal is 15.25

3 0

3 years ago

Point A is located at (-2, 2), and point M is located at (1,0). If point M is the midpoint of AB, find the location of point B.

bezimeni [28]

Answer:

B. $B = (4,-2)$

Step-by-step explanation:

GIven that $A = (-2, 2)$ and $M = (1, 0)$ , and that point M is the midpoint of AB, the midpoint can be determined as a vectorial sum of A and B. That is:

$M = \frac{1}{2}\cdot A + \frac{1}{2}\cdot B$

The location of B is now determined after algebraic handling:

$\frac{1}{2}\cdot B = M - \frac{1}{2}\cdot A$

$B = 2\cdot M -A$

Then:

$B = 2\cdot (1,0)-(-2,2)$

$B = (2\cdot 1, 2\cdot 0)-(-2,2)$

$B = (2,0) -(-2,2)$

$B = (4,-2)$

Which corresponds to option B.

5 0

2 years ago

Help please!! a pex test!!

amid [387]

Answer:

the domain is -5 to infinity

Explanation:

(

)

√

A square root is

≥

Here is a graph of the function

≥

−

{

√

[

−

]

}

6 0

2 years ago

This subject isn’t my fav so anyone wanna help?

Andrews [41]

Answer:

(1) 4 (2) -2

Step-by-step explanation:

4 0

2 years ago