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scZoUnD [109]
3 years ago
12

If each month in reno has 0.19 of rainfall as in August what would the total amount of rainfall be after 12 months

Mathematics
1 answer:
Sedbober [7]3 years ago
5 0

Answer:

0.76 of rainfall

Step-by-step explanation:

since there is only 4 months left after august multiply 0.19 x 4

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A restaurant chain has two locations in a medium-sized town and, believing that it has oversaturated the market for its food, is
scoray [572]

Answer:

Yes, since the test statistic value is greater than the critical value.

Step-by-step explanation:

Data given and notation

\bar X_{1}=360000 represent the mean for the downtown restaurant

\bar X_{2}=340000 represent the mean for the freeway restaurant

s_{1}=50000 represent the sample standard deviation for downtown

s_{2}=40000 represent the sample standard deviation for the freeway

n_{1}=36 sample size for the downtown restaurant

n_{2}=36 sample size for the freeway restaurant

t would represent the statistic (variable of interest)

\alpha=0.05 significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the true mean of revenue for downtown is higher than for freeway restaurant, the system of hypothesis would be:

Null hypothesis:\mu_{1}\leq \mu_{2}

Alternative hypothesis:\mu_{1} > \mu_{2}

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Determine the critical value.

Based on the significance level\alpha=0.05 and \alpha/2=0.025 we can find the critical values from the t distribution dith degrees of freedom df=36+36-2=55+88-2=70, we are looking for values that accumulates 0.025 of the area on the right tail on the t distribution.

For this case the value is t_{1-\alpha/2}=1.66

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

t=\frac{360000-340000}{\sqrt{\frac{50000^2}{36}+\frac{40000^2}{36}}}}=1.874

What is the p-value for this hypothesis test?

Since is a right tailed test the p value would be:

p_v =P(t_{70}>1.874)=0.033

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the true mean for the downtown revenue restaurant seems higher than the true mean revenue for the freeway restaurant.

The best option would be:

Yes, since the test statistic value is greater than the critical value.

5 0
3 years ago
Tim's mother has $24 left after buying school supplies. The next day she earns $232. She then divides all of the money equally a
Pie

Answer:

Tim has 64 dollars. I did the math and I know I'm right

8 0
3 years ago
Read 2 more answers
Help pls i need it fast
sergij07 [2.7K]
The correct answer is C. Let’s break this down with the distributive property.

5(6x+6)

30x+30

5(9-x)

45-5x

Now add and subtract like terms.
30x-5x=25x

30+45=75

Put the remaining numbers together.
25x+75 and there you go.
3 0
3 years ago
If i am 6 ft tall and he is 4 ft tall how tall are we together​
Elenna [48]

Answer:10

Step-by-step explanation:

6+4=10

6 0
3 years ago
Read 2 more answers
Write a paragraph comparing the two classes' semester grades. Be sure to compare the extremes, the quartiles, the medians, and t
NISA [10]

Answer:

Class second have higher score and have greater spread.

Step-by-step explanation:

For first box plot

\text{Minimum value }= 53

Q_1=62

Median=80

Q_3=86

\text{Maximum value }= 89

Range=Maximum-Minimum=89-53=36

IQR=Q_3-Q-1=86-62=24

For second box plot

\text{Minimum value }= 56

Q_1=62

Median=74

Q_3=89

\text{Maximum value }= 96

Range=Maximum-Minimum=96-56=40

IQR=Q_3-Q-1=89-62=27

First class has greater minimum value, it means first class has lower grades.

First quartile of both classes are same, it means equal number students in both classes have less than 62 marks.

First class has greater median.

second class has greater third quartile.

Second class has greater Maximum value.  It means second class have higher score than first class.

Second class has greater range. It means the data of second class has greater spread.

Second class has greater inter quartile range.  It means the data of second class has greater spread.

Therefore, the class second have higher score and have greater spread.

5 0
3 years ago
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