Answer:
B) always less than either of the original fractions
Step-by-step explanation:
We can easily Answer this by taking some values.
The question states that the two fractions, each have values between 0 and 1.
Let us say one of the fraction is 1/2 and the other fraction is 1/3 .
The product of the two fractions is 1/2 x 1/3 = 1/6 .
is lesser than both 1/2 and 1/3 .
So, the correct answer is that the product is always less than either of the original fractions.
A = (1/2)(b * h)
It is 1/2 times the product (which is the end result of multiplication of two values), of base (b) times height (h)
Answer:
![f^{-1}(x)=\sqrt[3]{x}-6](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D-6)
Step-by-step explanation:
![\sqrt[3]{x}=y+6](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%3Dy%2B6)
![\sqrt[3]{x}-6=y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D-6%3Dy)
Step-by-step explanation:
2(3x + 5y = -19)
6x + 10y = -38
5 (5x -2y = 16)
25x - 10y = 80
19x = 42
but idk from there the rest doesn't work Soo if u can find the prob and tell me I'll fix it.
Answer:
9:1
Step-by-step explanation:
432/48=9
9:1
