1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kupik [55]
3 years ago
14

This subject isn’t my fav so anyone wanna help?

Mathematics
1 answer:
Andrews [41]3 years ago
4 0

Answer:

(1) 4 (2) -2

Step-by-step explanation:

You might be interested in
Find the derivative of f(x) = negative 3 divided by x at x = -4.
olchik [2.2K]
Hope this helps you.

6 0
3 years ago
Read 2 more answers
A bird feeder 24 times using 6 cups each time. A bag of seeds holds 32 cups. How many bags of seed did he use?
pishuonlain [190]

First, let's find how many cups the bird feeder uses 24 times.

24 x 6 = (20 x 6) + (4 x 6) = 120 + 24 = 148 cups.

Now, let's divide 148 by 32.

148 ÷ 32 = 4.625 bags of seed.

I hope this helped!

6 0
3 years ago
A bag contains 4 red balls, 2 green balls, 3 yellow balls, and 5 blue balls. Find each probability for randomly removing balls w
AfilCa [17]

Answer:

\frac{15}{4802}, \frac{15}{9604}, \frac{9}{2401}, \frac{9}{4802}

Step-by-step explanation:

The bag has a total of (4+2+3+5) = 14 balls. Set up the proportions:

Red: \frac{4}{14}

green: \frac{2}{14}

yellow: \frac{3}{14}

blue: \frac{5}{14}

Now solve!

Removing 1 yellow, 1 red, 1 green, and 1 blue = \frac{3}{14} \cdot \frac{4}{14}  \cdot \frac{2}{14}  \cdot \frac{5}{14} =\frac{15}{4802}

Removing 1 blue, 1 green, 1 green, and 1 yellow = \frac{5}{14} \cdot \frac{2}{14}  \cdot \frac{2}{14}  \cdot \frac{3}{14} =\frac{15}{9604}

Removing 1 red, 1 red, 1 yellow, and 1 yellow = \frac{4}{14} \cdot \frac{4}{14}  \cdot \frac{3}{14}  \cdot \frac{3}{14} =\frac{9}{2401}

Removing 1 green, 1 yellow, 1 yellow, and 1 red = \frac{2}{14} \cdot \frac{3}{14}  \cdot \frac{3}{14}  \cdot \frac{4}{14} =\frac{9}{4802}

4 0
2 years ago
Mary is analyzing a quadratic function f(x) and a linear function g(x). Will they intersect? Which coordinates if they do? Negat
Umnica [9.8K]

Answer:

The graphs of the two function will not intersect.

Step-by-step explanation:

We are given a quadratic function f(x).

Also g(x) is given by a set of values as:

 x            g(x)

 1              -1

  2             0

  3              1

As g(x) is a linear function hence we find out the equation of g(x) by the slope intercept form of a line: y=mx+c

let g(x)=y

when x=1 ,   g(x)=-1

-1=m+c----(1)

when x=2   , g(x)=0

0=2m+c------(2)

Hence, on solving (1) and (2) by method of elimination we get:

m=1 and c=-2

Hence, the equation of g(x) is:

g(x)=x-2

So clearly from the graph we could see that the graph of the two functions will never intersect.


3 0
3 years ago
Read 2 more answers
Evaluate the expression to find out how much she will pay if she drives 100 miles.<br> 250 + 0.80m
zmey [24]
We plug 100 miles into 0.80. 250 + 0.80(100) is 250 + 80. 250 + 80 is 330.
7 0
2 years ago
Other questions:
  • PLEASE SOMEONE HELP ME!! Use the square root property to solve the following equation t^2-75=0
    12·1 answer
  • What’s 5 equivalent ratios to 27:9
    10·2 answers
  • population mean =72 and standard deviation =10, what is standard error of distribution of sample means for n=4 and n=25
    12·1 answer
  • Write <br> y = 3x2-12x +11 in vertex form. please show work
    15·2 answers
  • Guide Micah harvested 28 watermelons from his garden. He sold w watermelons at the market. Which expression describes the number
    15·1 answer
  • Help plzzz!! <br><br> find the value of x
    9·1 answer
  • At the deli, two smoked turkey subs and five veggie subs cost $29. Four smoked turkey subs and three veggie subs cost $30. (A) C
    7·1 answer
  • Please look at the image for the question
    14·1 answer
  • Find the value of x.<br> 30 <br> 17
    9·1 answer
  • NEED HELP ASAP WILL GIVE BRAINLEST... 30 POINTS!!!!!
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!