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stiks02 [169]
2 years ago
10

15. If the point (5,k) lies on the line represented by the equation 2x + y = 9, the value of k is....

Mathematics
1 answer:
guajiro [1.7K]2 years ago
5 0

Answer:

The answer is C.

Step-by-step explanation:

Given that (5,k) lies on the line that has the equation of 2x + y = 9. So in order to find k, you have to substitute the coordinates into the equation :

2x + y = 9

Let x = 5,

Let y = k,

2(5) + k = 9

10 + k = 9

k = 9 - 10

k =  - 1

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All of the expressions that have the same value as LaTeX: 892\div8892 ÷ 8. Group of answer choices LaTeX: 8920\div808920 ÷ 80 La
algol13

Answer:

(a) 8920\div80

(e) 0.892\div0.008

Step-by-step explanation:

Given

892\div8

Required

Select equivalent expression

8920\div80

894\div10

89.2\div0.08

8.92\div0.8

0.892\div0.008

Start  by solving the given expression (using a calculator)

892\div8 = 111.5

Then we solve the given options (using a calculator)

(a) 8920\div80

8920\div80 = 111.5

(b) 894\div10

894\div10 = 89.4

(c) 89.2\div0.08

89.2\div0.08 = 1115

(d) 8.92\div0.8

8.92\div0.8 = 11.15

(e) 0.892\div0.008

0.892\div0.008 = 111.5

The equivalent expressions are (a) and (e)

5 0
2 years ago
Find all values of x such that sin 2x = sin x and 0 ≤ x ≤ 2π.
jarptica [38.1K]
Hello : 
<span> sin 2x = sin x and 0 ≤ x ≤ 2π.
all solutions : 
2x= x +2k</span>π    or x= π -x +2kπ ..... k in : Z
x = 2kπ  or : x = π/2 + kπ 
but :
 <span>0 ≤ x ≤ 2π
</span><span>all values of x such that sin 2x = sin x and 0 ≤ x ≤ 2π are : 
</span>k = 0 : x=0    , x= π/2
k=1 : x=2 π    , x=3π/2
5 0
3 years ago
Four ninths plus five sixths
sergey [27]

Answer:

1 5/18

one and five eighteenths  

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Write a polynomial function of minimum degree in standard form with real coefficients whose zeros and their multiplicities inclu
Softa [21]

<u>Answer-</u>

<em>The polynomial function is,</em>

y=x^4-10x^3+38x^2-64x+40

<u>Solution-</u>

The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1

The general form of the equation will be,

\Rightarrow y=(x-(2))^2(x-(3+i))(x-(3-i))   ( ∵ (3-i) is the conjugate of (3+i) )

\Rightarrow y=(x-2)^2(x-3-i)(x-3+i)

\Rightarrow y=(x^2-4x+4)((x-3)-i)((x-3)+i)

\Rightarrow y=(x^2-4x+4)((x-3)^2-i^2)

\Rightarrow y=(x^2-4x+4)((x^2-6x+9)+1)

\Rightarrow y=(x^2-4x+4)(x^2-6x+10)

\Rightarrow y=x^2x^2-6x^2x+10x^2-4x^2x+4\cdot \:6xx-4\cdot \:10x+4x^2-4\cdot \:6x+4\cdot \:10

\Rightarrow y=x^4-10x^3+14x^2+24x^2-40x-24x+40

\Rightarrow y=x^4-10x^3+38x^2-64x+40

Therefore, this is the required polynomial function.


4 0
3 years ago
What is the square root of 1000/100000
Mrac [35]
Remember that \sqrt{\frac{x}{y} }= \frac{ \sqrt{x} }{ \sqrt{y} } so
\sqrt{\frac{1000}{100000} }= \frac{ \sqrt{1000} }{ \sqrt{100000} }
find the individual square roots
\frac{ \sqrt{1000} }{ \sqrt{100000} }=\frac{ 10\sqrt{10} }{ 100\sqrt{10} } = \frac{10}{100} times \frac{ \sqrt{10} }{ \sqrt{10} }  = \frac{10}{100}   times 1= \frac{1}{10}

answer is 1/10
7 0
2 years ago
Read 2 more answers
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