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2 years ago

15. If the point (5,k) lies on the line represented by the equation 2x + y = 9, the value of k is....

Mathematics

1 answer:

guajiro [1.7K]2 years ago

5 0

Answer:

The answer is C.

Step-by-step explanation:

Given that (5,k) lies on the line that has the equation of 2x + y = 9. So in order to find k, you have to substitute the coordinates into the equation :

$2x + y = 9$

Let x = 5,

Let y = k,

$2(5) + k = 9$

$10 + k = 9$

$k = 9 - 10$

$k = - 1$

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All of the expressions that have the same value as LaTeX: 892\div8892 ÷ 8. Group of answer choices LaTeX: 8920\div808920 ÷ 80 La

algol13

Answer:

$(a)$ $8920\div80$

$(e)$ $0.892\div0.008$

Step-by-step explanation:

Given

$892\div8$

Required

Select equivalent expression

$8920\div80$

$894\div10$

$89.2\div0.08$

$8.92\div0.8$

$0.892\div0.008$

Start by solving the given expression (using a calculator)

$892\div8$ $= 111.5$

Then we solve the given options (using a calculator)

$(a)$ $8920\div80$

$8920\div80$ $= 111.5$

$(b)$ $894\div10$

$894\div10$ $= 89.4$

$(c)$ $89.2\div0.08$

$89.2\div0.08$ $= 1115$

$(d)$ $8.92\div0.8$

$8.92\div0.8$ $= 11.15$

$(e)$ $0.892\div0.008$

$0.892\div0.008$ $= 111.5$

The equivalent expressions are (a) and (e)

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2 years ago

Find all values of x such that sin 2x = sin x and 0 ≤ x ≤ 2π.

jarptica [38.1K]

Hello :
 sin 2x = sin x and 0 ≤ x ≤ 2π.
all solutions :
2x= x +2kπ or x= π -x +2kπ ..... k in : Z
x = 2kπ or : x = π/2 + kπ
but :
0 ≤ x ≤ 2π
all values of x such that sin 2x = sin x and 0 ≤ x ≤ 2π are :
k = 0 : x=0 , x= π/2
k=1 : x=2 π , x=3π/2

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3 years ago

Four ninths plus five sixths

sergey [27]

Answer:

1 5/18

one and five eighteenths

Step-by-step explanation:

4 0

3 years ago

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Write a polynomial function of minimum degree in standard form with real coefficients whose zeros and their multiplicities inclu

Softa [21]

Answer-

The polynomial function is,

$y=x^4-10x^3+38x^2-64x+40$

Solution-

The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1

The general form of the equation will be,

$\Rightarrow y=(x-(2))^2(x-(3+i))(x-(3-i))$ ( ∵ (3-i) is the conjugate of (3+i) )

$\Rightarrow y=(x-2)^2(x-3-i)(x-3+i)$

$\Rightarrow y=(x^2-4x+4)((x-3)-i)((x-3)+i)$

$\Rightarrow y=(x^2-4x+4)((x-3)^2-i^2)$

$\Rightarrow y=(x^2-4x+4)((x^2-6x+9)+1)$

$\Rightarrow y=(x^2-4x+4)(x^2-6x+10)$

$\Rightarrow y=x^2x^2-6x^2x+10x^2-4x^2x+4\cdot \:6xx-4\cdot \:10x+4x^2-4\cdot \:6x+4\cdot \:10$

$\Rightarrow y=x^4-10x^3+14x^2+24x^2-40x-24x+40$

$\Rightarrow y=x^4-10x^3+38x^2-64x+40$

Therefore, this is the required polynomial function.

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3 years ago

What is the square root of 1000/100000

Mrac [35]

Remember that $\sqrt{\frac{x}{y} }= \frac{ \sqrt{x} }{ \sqrt{y} }$ so
$\sqrt{\frac{1000}{100000} }= \frac{ \sqrt{1000} }{ \sqrt{100000} }$
find the individual square roots
$\frac{ \sqrt{1000} }{ \sqrt{100000} }$ = $\frac{ 10\sqrt{10} }{ 100\sqrt{10} } = \frac{10}{100} times \frac{ \sqrt{10} }{ \sqrt{10} } = \frac{10}{100} times 1= \frac{1}{10}$

answer is 1/10

7 0

2 years ago

Read 2 more answers