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Colt1911 [192]
3 years ago
8

Samantha had $15.She spends $2.25 on admission to the ice skating rink, $2.15 to rent ice skates and $1.35 each for 2 hot chocol

ates.How much money does she have left?
Mathematics
1 answer:
jolli1 [7]3 years ago
7 0

Answer: $7.90

Step-by-step explanation:

When we see how much she spent on the total cost of renting skates, getting in, and getting hot chocolate, we can see that she is going to subtract all of that from the total cost.

$15.00 - 2.25 = 12.75

12.75 - 2.15 = 10.60

10.60 - 1.35 = 9.25

9.25 - 1.35 = 7.90 remaining

We know that she payed 2.25 to get in, 2.15 for skate rental, and 1.35 for each hot chocolate she purchased which in this case is 2. We need to subtract all of this from 15 and get the final answer

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A rectangular box is constructed in 3-space with one corner at the origin and other vertices at (1, 0, 0), (0, 4, 0), (0, 0, 2).
77julia77 [94]

The space diagonal will have length ...

... d = √(1² +4² +2²) = √(1 +16 +4) = √21

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This can be found using the Pythagorean theorem. A drawing can help. Find the length of any face diagonal, then use that length as the leg of a right triangle whose hypotenuse is the space diagonal and whose other leg is the edge length not used in the first calculation.

7 0
4 years ago
A business executive bought 40 stamps for
alekssr [168]

Answer:

32 33-cent stamps, 8 23-cent stamps

Step-by-step explanation:

In order to solve this question, we need to set up a system of equations. Also known as solving for two variables (the number of each stamp).

Let's set x to be the number of 33-cent stamps. Similarly, let's set y to be the number of 23-cent stamps.

To make our first equation, let's think about the number of stamps total we have. We can say:

x + y =40

<em>(AKA - The number of 33-cent stamps, plus the number of 23-cent stamps, equals 40 stamps.)</em>

Now, let's make an equation for the cost of these stamps.

0.33x + 0.23y = 12.40

<em>(AKA - The cost of the stamps in total, should equal $12.40).</em>

So now, we have our two equations:

x + y =40\\0.33x+0.23y=12.40

If you have a TI-84 graphing calculator, you can go to apps -> polysmlt2 -> simultaneous eqn solver, and then input these equations into the menu. This will solve the problem for you.

If you need to do this manually, let's use substitution. Condense our first equation to make it more substitutable.

x+y=40\\x=40-y

Now, let's put this into our second equation.

0.33x+0.23y=12.40\\0.33(40-y)+0.23y=12.40

Distribute, and solve for y.

13.2-0.33y +0.23y =12.40\\13.2-0.1y=12.40\\-0.1y=-0.8\\y=8

Now, we plug this into one of our equations.

x+y=40\\x+8=40\\x=32

In the end, we have thirty-two 33-cent stamps, and eight 23-cent stamps.

3 0
1 year ago
Solve the equation: 1/6d+2/3=1/4(d-2)
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d/6+2/3=1/4(d-2)

d/6+2/3=d-2/4

2d+8=3(d-2)

2d+8=3d-6

8=3d-6-2d

8=d-6

8+6=d

14=d

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Is 8:2 greater than 5:1? <br><br> I need someone to help me clarify if this is correct. Thanks.
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Answer:

No, 8:2 = 4:1 which is less than 5:1

Step-by-step explanation:

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