Question

Which equation, when graphed, has x-intercepts at (8,0) and (-2,0) and a y-intercept at (0,-48)?

Answer 1

Answer:

3rd answer f(x) = 3(x-8)(x+2)

Step-by-step explanation:

The x-intercepts are the points at which the parabola intersects the x-axis.

Function y = a(x - r₁)(x - r₂) is in factored form, where r₁ and r₂ are x-intercepts so if r₁ = 8 and r₂ = -2 then

y = a (x-8)(x-(-2))=a(x-8)(x+2)

For y intercept plug in (0,-48) in equation and calculate a:

-48 = a (0-8)(0+2)

-48 = a(-8)(+2)

-48 = -16a divide by -16

a = 3

Function is y = 3(x-8)(x+2)