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Rudik [331]
3 years ago
9

The vertex of this parabola is at (2, -4). When the y-value is -3, the x-value is -3. What is the coefficient of the squared ter

m in the parabola's equation?A.-1B.-5C.1D.5
Mathematics
1 answer:
attashe74 [19]3 years ago
7 0

Answer:

a = 1/25

Step-by-step explanation:

The vertex form of the parabola is

y = a(x-h)^2 +k

where (h,k) is the vertex

y = a(x-2)^2 -4

We have a point on the parabola (-3,-3) so substitute this into the equation

-3 = a(-3-2)^2 -4

-3 = a(-5)^2 -4

Add 4 to each side

-3+4 = a(25) +4-4

1 = 25a

Divide each side by 25

1/25 = a

y = 1/25(x-2)^2 -4

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8 0
3 years ago
Identify the vertex for the graph of y = −3x^2 + 6x − 4
algol [13]

Answer:

the vertex is (1,-1)

Step-by-step explanation:

y = −3x^2 + 6x − 4


the vertex is at

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3 0
3 years ago
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-100 - ___= 65<br> A. 35<br> B. 65<br> C. -35<br> D. -165
Softa [21]

Answer:

D

Step-by-step explanation:

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