A. Alright, we want to multiply one equation by a constant to make it cancel out with the second. Since the first equation has a "blank" y, let's multiply the first equation by <em>2</em>.
3x-y=0 → 2(3x-y=0) = 6x - 2y = 0
5x+2y=22
The answer for this part would be: 6x - 2y = 0 and 5x + 2y = 22
B. So now we combine them:
6x - 2y = 0
+ + +
5x + 2y = 22
= = =
11x + 0 = 22 ← The answer
C. Now that we have the equation 11x = 22, we solve for x
11x = 22 ← Divide both sides by 11
x = 2 ← The answer
D. Now that we have x=2, we plug that back in to 5x+2y=22 and solve for y:
5(2)+2y = 22
10 + 2y = 22
2y = 12
y = 6
<u>Therefore, the solution to this problem is x = 2 and y = 6</u>
<span>sin 90° = 1
</span>
cos 0° = 1
There's a simple formula : <em>sin θ = cos (90°- θ)</em> or <em>cos θ = sin (90°- θ) </em>
So : cos 0° = sin (90° - 0°) = sin 90° = 1
Answer:
.
Step-by-step explanation:
to give b from both equation the same value
a:b:c = 8:6:9
a = 8
b = 6
c = 9
Answer:
x = 2, x = 4
Step-by-step explanation:
The equation y = 10 - 9x is a linear equation and the value of either y or x can be found by substituting the given values of either y or x.
given that y = -8, and substituting this into equation y = 10 - 9x,
we have, -8 = 10 - 9x
10 + 8 = 9x
9x = 18; dividing both sides by 9
x = 2
given that y = -26, and substituting this into equation y = 10 - 9x,
we have, -26 = 10 - 9x
10 + 26 = 9x
9x = 36; dividing both sides by 9
x = 4
