Answer:
See attachment for flowchart
Explanation:
Required
Flowchart to fine even from 1 to 50
The flowchart has been attached.
The rough algorithm (explanation) of the flowchart is as follows.
1. Start
2. Initialize num to 1
3. Check if num is less than or equal to 50
3.1 If yes
3.1.1 Check if num is even
3.1.1.1 If yes
3.1.1.2 Print num
3.1.3 Increase num by 1
3.2 If num is greater than 50
3.2.1 Stop
4. Goto 3
Answer:
- import java.util.Arrays;
- public class Main {
-
- public static void main(String[] args) {
- String [] first = {"David", "Mike", "Katie", "Lucy"};
- String [] middle = {"A", "B", "C", "D"};
- String [] names = makeNames(first, middle);
-
- System.out.println(Arrays.toString(names));
- }
-
- public static String [] makeNames(String [] array1, String [] array2){
-
- if(array1.length == 0){
- return array1;
- }
-
- if(array2.length == 0){
- return array2;
- }
-
- String [] newNames = new String[array1.length];
-
- for(int i=0; i < array1.length; i++){
- newNames[i] = array1[i] + " " + array2[i];
- }
-
- return newNames;
- }
- }
Explanation:
The solution code is written in Java.
Firstly, create the makeNames method by following the method signature as required by the question (Line 12). Check if any one the input string array is with size 0, return the another string array (Line 14 - 20). Else, create a string array, newNames (Line 22). Use a for loop to repeatedly concatenate the string from array1 with a single space " " and followed with the string from array2 and set it as item of the newNames array (Line 24-26). Lastly, return the newNames array (Line 28).
In the main program create two string array, first and middle, and pass the two arrays to the makeNames methods as arguments (Line 5-6). The returned array is assigned to names array (Line 7). Display the names array to terminal (Line 9) and we shall get the sample output: [David A, Mike B, Katie C, Lucy D]
Answer:
Your response is correct.
I hope this helped at all.
difference between engineering and architecture are.
A engineer is a person whose job involves designing and building engines, machines, roads, bridges ,etc .
While architect design buildings only.
Answer:
Shows the programming checking if num1 is greater than num2
Explanation:
So num1 and num2 are inputs
for you to code this you would need to put
num1=int(input("What is your first number? ))
and the same for num2 except change num1 for num 2 and first for second
When the input is completed, the computer will check if num 1 is greater than num2
it will do this by using a code something like:
if num1>num2:
Print("Your first input was greater than your second")
But in this example if it greater it just ends
But if it was less than you would put
if num1>num2:
Print("Your first input was greater than your second")
elif num1<num2:
Print("Your first input is less than your second")
So basically this code shows the computer checking if one number is greater than the other or not
