A rocket is launched from the top of a 100-foot cliff with an initial velocity of 34 feet per second. The height of the rocket t
seconds after launch is given by the equation h=−16t2+34t+100. How high will the rocket be after 1 second?
1 answer:
Answer:
118 feet
Step-by-step explanation:
h= -16t² + 34t +100
In order to find the height of the rocket after 1 second, we substitute t=1 in the above equation
h= -16(1)² + 34(1) +100
h=-16 + 34 +100
h=118 feet
Thus, the rocket will be 118 feet high after 1 second
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