We can do this easily. Since we know that the numerator is more than the denominator, we need to know by how much.
39-28=11; It's only 11 more, which means 11/28 would be the fraction and the whole number is 1.
39/28= 1 11/28
Answer: d. ∠u ≅ ∠v
Step-by-step explanation:
We know that when two triangles are congruent then their corresponding parts are congruent.
This property is known as CPCTC.
Given: triangle stu is congruent to triangle vwx
Thus, all corresponding sides are congruent
a.segment st ≅ segment vw and d. segment su ≅ segment vx , both are correct.
All corresponding angles are congruent,thus
∠s ≅ ∠v
∠t ≅ ∠w
∠u ≅ ∠x
Thus, d is the option which is not true.
Answer:
- c(n) = 320·0.96^n
- 28 years
Step-by-step explanation:
Each year, the class size is multiplied by 1 - 4% = 96% = 0.96. After n years, it has been multiplied by that number n times. Repeated multiplication is signified using an exponent.
Class size (c) can be modeled by ...
c(n) = 320·0.96^n
__
You want to find n such that c(n) = 100. Put in that value and solve.
100 = 320·0.96^n
100/320 = 0.96^n . . . . . . . divide by 320
log(100/320) = n·log(0.96) . . . . . . . take logs
log(100/320)/log(0.96) = n ≈ 28.4932
In about 28 years, the class will have 100 students.
Answer:
Step-by-step explanation:
y=-3x+5
y=-3(1)+5
y=-3+5
y=2
(1,2)
y=-3x+5
y=-3(2)+5
y=-6+5
y=-1
(2,-1)
y=-3x+5
y=-3(3)+5
y=-15+5
y=-10
(3,-10)
