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3 years ago

Linda earns $600 each week working her full time job. Her employer has a 16% tax deduction on all monies earned each week

Mathematics

1 answer:

shutvik [7]3 years ago

3 0

Answer:

$504 a week

Step-by-step explanation:

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A student multiplies (4+5i) (3-2i) incorrectly and obtains 12-10i what is the students mistakes

Rufina [12.5K]

Answer:

1. In the multiplication of the imaginary parts, the student forgot to square of i. OR

2. The student has only multiplied the real parts and the imaginary parts.

Correct value $=22+7i$ .

Step-by-step explanation:

The given expression is

$(4+5i)(3-2i)$

A student multiplies (4+5i) (3-2i) incorrectly and obtains 12-10i.

Student's mistake can be either 1 or second:

1. In the multiplication of the imaginary parts, the student forgot to square of i.

2. The student has only multiplied the real parts and the imaginary parts.

$(4+5i)(3-2i)=4\times 3+5\times (-2)i=12-10i$

Which is not correct. The correct steps are shown below.

Using distributive property, we get

$4(3-2i)+5i(3-2i)$

$4(3)+4(-2i)+5i(3)+5i(-2i)$

$12-8i+15i-10i^2$

$12+7i-10(-1)$ $[\because i^2=-1]$

$12+7i+10$

$22+7i$

Therefore, the correct value of $(4+5i)(3-2i)$ is $22+7i$ .

4 0

3 years ago

Write five names of 64

solong [7]

1)64

2)sixty four

3)4³

4)8²

5)6*10 + 4*1

5 0

3 years ago

Solve this equation pls

Aleksandr-060686 [28]

Answer:

${ \rm{y = \frac{3 \sqrt{x} + 2x}{ {4x}^{2} } }} \\$

• We are gonna use the quotient rule

${ \boxed{ \bf{ \frac{dy}{dx} = \frac{ {\huge{v} } \frac{du}{dx} - { \huge{u}} \frac{dv}{dx} }{ {v}^{2} } }}} \\$

u is (3√x + 2x)
v is 4x²
du/dx is 3/2√x
dv/dx is 8x

• Therefore:

${ \rm{ \frac{dy}{dx} = \frac{(4 {x}^{2})( \frac{3}{2 \sqrt{x} }) - (3 \sqrt{x} + 2x)(8x) }{16 {x}^{4} } }} \\ \\ { \rm{ \frac{dy}{dx} = \frac{(6 {x}^{2})( {x}^{ - \frac{1}{2} } ) - (24 {x}^{ \frac{3}{2} } + 16 {x}^{2} ) }{16 {x}^{4} } }} \\ \\ { \rm{ \frac{dy}{dx} = \frac{ 6 {x}^{ \frac{3}{2} } - {24x}^{ \frac{3}{2} } - {16x}^{2} }{16 {x}^{4} } }} \\ \\ { \rm{ \frac{dy}{dx} = \frac{ - 18 {x}^{ \frac{3}{2} } - 16 {x}^{2} }{16 {x}^{4} } }} \\ \\ { \rm{ \frac{dy}{dx} = - 2 {x}^{ \frac{3}{2} } (9 + 8 {x}^{ \frac{4}{3} } ) \div 16 {x}^{4} }} \\ \\ { \boxed{ \boxed{ \rm{ \: \: \frac{dy}{dx} = - \frac{8 \sqrt{ {x}^{ \frac{8}{3} }} + 9}{8x {}^{ \frac{8}{3} } } \: \: }}}}$