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slega [8]
3 years ago
9

Derive the equation of the parabola with a focus at (–5, 5) and a directrix of y = -1.

Mathematics
2 answers:
Elza [17]3 years ago
6 0
( x + 5 )^2 = - ( y - 5 )
Dvinal [7]3 years ago
4 0

Answer:

(x+5)^2=12(y-2)

Step-by-step explanation:

We are given that focus of parabola at (-5,5).

Equation of directrix y=-1

We have to derive the equation of parabola

We know that the parabola is the set of points (x,y) equally distant from (-5,5) and (x,-1).

Distance formula

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Apply this formula

\sqrt{(x+5)^2+(y-5)^2}=\sqrt{(x-x)^2+(y+1)^2}

Squaring on both sides then we get

(x+5)^2+(y-5)^2=(y+1)^2

(x+5)^2+y^2-10y+25=y^2+2y+1  ((a-b)^2=a^2+b^2-2ab,(a+b)^2=a^2+b^2+2ab)

(x+5)^2=y^2+2y+1-y^2+10y-25

(x+5)^2=12y-24

(x+5)^2=12(y-2)

This is required equation of parabola along y- axis.

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Answer:

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Step-by-step explanation:

A third degree polynomial can be written in function of it's zeros x_1, x_2, x_3 the following way:

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