All categories

3 years ago

What does ⅔ X 15 = equal

Mathematics

2 answers:

Helga [31]3 years ago

7 0

Answer:

Step-by-step explanation:

2/3*15

2/3* 15/1

Multiply the numerators

2*15 =30

And the denominators

3*1 =3

30/3

Divide the top and bottom by3

10/1

frez [133]3 years ago

6 0

Answer:

Step-by-step explanation:

(2/3) x (15)

is the same as

(2/3) x (15/1)

which means after you multiply them you get:

30/3

which simplifies to:

You might be interested in

Please solve this problem

musickatia [10]

Answer:

Step-by-step explanation:

Multiply each side by 6x.

4x+x $\sqrt{3\\$ = 30

Square both sides.

16x^2+3x^2=900 = 19x^2

x^2= about $\sqrt{47.37}$

x=6.9

5 0

3 years ago

Here is a formula P=3T work out the value of P when T =10

xeze [42]

Step-by-step explanation:

p=3T

when T=10

p=3×10

p=30

7 0

2 years ago

Read 2 more answers

HELP PLEASE!!!!!! PLEASE!!!!

Nezavi [6.7K]

Answer:

x = 15°

Step-by-step explanation:

7x + 28° = 133° { being vertically opposite angles }

7x = 133° - 28°

7x = 105°

x = 105° / 7

x = 15°

< WPZ = 133° {being vertically opposite angles }

< WPZ = 7x + 28° = 7 * 15 + 28° = 133°

Hope it will help :)❤

4 0

3 years ago

Read 2 more answers

PLZZ HELP ME WITH THIS

Slav-nsk [51]

Length= How high
Layer 1 length is 1 block high and the length is 2.

3 0

3 years ago

What are the period and phase shift for f(x) = 3 tan(4x + π)?

Y_Kistochka [10]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\

\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ horizontal or "phase" shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}$

now.. with that template above in mind, let's see yours

$\bf \begin{array}{lllllll}
f(x)=&3tan(&4x+&\pi )\\
f(x)=&3tan(&4x+&1\pi )&+0\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

7 0

3 years ago