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tatuchka [14]
3 years ago
12

Mrs.Swanson made 1/2 of a pound of fudge to share it equally among 6 students in a reading group. How much fudge would each chil

d get?
Mathematics
1 answer:
Alexxx [7]3 years ago
6 0

Answer:  1/12

Step-by-step explanation: 1/2 / 6 = 1/2 X 1/6 = 1/12

To get this equation you have to perform KCF which stands for Keep Change Flip. KCF is only to be used for division fraction problems. KCF means you Keep the first Fraction, then change the division sign into a multiplication sign. and last flip the last fraction.

<h2>HOPE THIS HELPED!!</h2>

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Elsa scores eight points in six minutes if she could send years at this rate how many points will she score 9 minutes
Minchanka [31]

Answer:

12 points

Step-by-step explanation:

9 is 1.5 times 6, so 8 times 1.5 gives you the answer of 12 points.

5 0
3 years ago
If BC = 61 and AB = 82, what is the length of AC?
Nitella [24]

Answer:

54.8

Step-by-step explanation:

Pythagorean theorem is a^2+b^2=c^2.

Plug the given values in to get 61^2+b^2=82^2

61^2 is 3,721 and 82^2 is 6,724.

6,724-3,721 is 3,003.

The square root of 3,003, rounded to a reasonable value, is 54.8.

The length of AC is 54.8.

4 0
3 years ago
Jordan has
attashe74 [19]
(1/3)/(5)= 1/3 * 1/5 = 1/15 of a chocolate bar each friend gets
7 0
3 years ago
Solve the system of equations by the substitution method:<br> 4x-y = 35<br> 7x + 6y = 38
Leokris [45]

Answer:

x=8 and y=−3

8 0
3 years ago
point b on the ground is 5 cm from point E at the entrance to Ollie's house. He is 1.8 m tall and is standing at Point D, below
enot [183]

Point B on the ground is 5 cm from point E at the entrance to Ollie's house.

Ollie is at a distance of 2.45 m from the entrance to his house when he first activates the sensor.

The complete question is as follows:

Ollie has installed security lights on the side of his house that is activated by a  sensor. The sensor is located at point C directly above point D. The area covered by the sensor is shown by the shaded region enclosed by triangle ABC. The distance from A to B is 4.5 m, and the distance from B to C is 6m. Angle ACB is 15°.

The objective of this information is:

  • To find angle CAB and;
  • Find the distance Ollie is from the entrance to his house when he first activates the sensor.

The diagrammatic representation of the information given is shown in the image attached below.

Using  cosine rule to determine angle CAB, we have:

\mathbf{\dfrac{AB}{Sin \hat {ACB}} = \dfrac{BC}{Sin \hat {CAB}}= \dfrac{CA}{Sin \hat {ABC}}}

Here:

\mathbf{\dfrac{AB}{Sin \hat {ACB}} = \dfrac{BC}{Sin \hat {CAB}}}

\mathbf{\dfrac{4.5}{Sin \hat {15^0}} = \dfrac{6}{Sin \hat {CAB}}}

\mathbf{Sin \hat {CAB} = \dfrac{Sin 15 \times 6}{4.5}}

\mathbf{Sin \hat {CAB} = \dfrac{0.2588 \times 6}{4.5}}

\mathbf{Sin \hat {CAB} = 0.3451}

∠CAB = Sin⁻¹ (0.3451)

∠CAB = 20.19⁰

From the diagram attached;

  • assuming we have an imaginary position at the base of Ollie Standing point called point F when Ollie first activates the sensor;          

Then, we can say:

∠CBD = ∠GBF

∠GBF = (CAB + ACB)      

(because the exterior angles of a Δ is the sum of the two interior angles.

∠GBF = 15° + 20.19°

∠GBF = 35.19°

Using the trigonometric function for the tangent of an angle.

\mathbf{Tan \theta = \dfrac{GF}{BF}}

\mathbf{Tan \ 35.19  = \dfrac{1.8 \ m }{BF}}

\mathbf{BF  = \dfrac{1.8 \ m }{Tan \ 35.19}}

\mathbf{BF  = \dfrac{1.8 \ m }{0.7052}}

BF = 2.55 m

Finally, the distance of Ollie║FE║ from the entrance of his bouse is:

= 5 - 2.55 m

= 2.45 m

Therefore, we can conclude that Ollie is at a distance of 2.45 m from the entrance to his house when he first activates the sensor.

Learn more about exterior angles here:

8 0
3 years ago
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