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3 years ago

Please help me i need the answer if i knew it i will complete all of them by my self (: .

Mathematics

2 answers:

gladu [14]3 years ago

5 0

The right answer is 100 units^2

please see the attached picture for full solution

Hope it helps

Good luck on your assignment,

Svetach [21]3 years ago

4 0

For area you would times the two sides you have together
10 x 10 = 100

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4 /5 + 3 /15 - 2 /3 =???????

sergey [27]

Answer:

the answer is 1/3

Step-by-step explanation:

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2 years ago

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MAVERICK [17]

Answer:

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Step-by-step explanation:

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3 years ago

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GuDViN [60]

Answer:

See below.

Step-by-step explanation:

$\frac{6z^2-12z}{4z^2-16z+16} +\frac{3z}{z^2-z-2} \\\\$

First, factor the numerators and the denominators:

$=\frac{6z(z-2)}{4(z^2-4x+4)}+\frac{3z}{z^2-z-2}\\=\frac{6z(z-2)}{4(z-2)^2}+\frac{3z}{(z-2)(z+1)}\\=\frac{3z}{2(z-2)}+\frac{3z}{(z-2)(z+1)}$

Now, make the two denominators equivalent. To do this, we can multiply the first term by (z+1) and multiply the second term by 2. This will give us:

$(\frac{z+1}{z+1} )(\frac{3z}{2(z-2)})+(\frac{2}{2})(\frac{3z}{(z-2)(z+1)})\\=\frac{3z(z+1)}{2(z-2)(z+1)}+\frac{6z}{2(z-2)(z+1)} \\$

Now, combine them since they have a common denominator:

$=\frac{3z^2+3z+6z}{2(z-2)(z+1)}\\ =\frac{3z^2+9z}{2(z-2)(z+1)} \\=\frac{3z(z+3)}{2(z-2)(z+1)}$

This cannot be simplified further.

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3 years ago

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Ira Lisetskai [31]

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Its the only one going down 3 and over 1.

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