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1 year ago

4 /5 + 3 /15 - 2 /3 =???????

Mathematics

2 answers:

sergey [27]1 year ago

5 0

Answer:

the answer is 1/3

Step-by-step explanation:

3/15 equals 1/5 so 1/5+4/5=1 so 1-2/3=1/3

andrew11 [14]1 year ago

3 0

Answer:

1/3

Step-by-step explanation:

1) Simplify 3/15 to 1/5.

4/5 + 1/5 - 2/3

2) Find the Least Common Denominator (LCD) of D) of $\frac{4}{5},\frac{1}{5},\frac{2}{3}$ In other words, find the Least Common Multiple (LCM) of 5,5,3.

Method 1: By Listing Multiples

1) List the multiples of each number.

Multiples of 5 : 5, 10, 15, ...

Multiples of 3 : 3, 6, 9, 12, 15, ...

2) Find the smallest number that is shared by all rows above. This is the LCM.

LCM = 15

Method 2: By Prime Factors

1) List the prime factors of each number.

Prime Factors of 5 : 5

Prime Factors of 3 : 3

2) Find the union of these primes.

3,5

Multiply these numbers: 3 × 15 = 15. This is the LCM.

LCM = 15

3) Make the denominators the same as the LCD.

$\frac{4*3}{5*12} +\frac{1*3}{5*3} -\frac{2*5}{3*5}$

4) Denominators are now the same.

12/15 + 3/15 - 10/15

5) Join the denominators.

12 + 3 - 10/ 15

6) Simplify.

5/15

7) Simplify.

1/3

Decimal Form: 0.333333

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3 years ago

Someone help me please and thank you!! ASAP :(

pantera1 [17]

<h3>Answer: Choice D) </h3>

Work Shown:

$(f+g)(x) = f(x)+g(x)\\\\(f+g)(x) = \frac{x-23}{x^2+9x-36}+\frac{1}{x+12}\\\\(f+g)(x) = \frac{x-23}{(x+12)(x-3)}+\frac{1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+x-3}{x^2+9x-36}\\\\(f+g)(x) = \frac{2x-26}{x^2+9x-36}\\\\$