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Rasek [7]
3 years ago
14

What is What is the measure of angle B? A. 30° C. 35°

Mathematics
1 answer:
Setler [38]3 years ago
3 0

Answer:

A

Step-by-step explanation:

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The answer for this question
Andrews [41]

Answer:

Right triangle

Step-by-step explanation:

Pythagorean Thereom can only be used on right triangles

8 0
2 years ago
Will a 9/32 inch diameter pin fit into a reamed hole with a diameter of 0.278 inch? (Do not round off your answer and express it
ollegr [7]

Answer:

9/32 inch diameter pin will not fit into a reamed hole with a diameter of 0.278 inch

Step-by-step explanation:

Diameter of reamed hole = 0.278 inch

Radius of reamed hole = \frac{0.278}{2} =0.139

Surface area of reamed hole = \pi r^2

Surface area of reamed hole = 3.14 \times  (0.139)^2

Surface area of reamed hole = 0.06066794

Diameter of pin = \frac{9}{32}

Radius of pin =\frac{9}{64}

Surface area of pin = \pi r^2 = 3.14 \times ( \frac{9}{64})^2=0.0620

Since the surface area of pin is more than the surface area of hole .

So, a 9/32 inch diameter pin will not fit into a reamed hole with a diameter of 0.278 inch

7 0
3 years ago
Evaluate 4-2f when f=1
iren2701 [21]
The answer is 2 ....
.. 
7 0
3 years ago
Read 2 more answers
Help please. I need this in a few minutes
Ghella [55]

Answer:

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Student performance across discussion sections: A professor who teaches a large introductory statistics class (197 students) wit
adell [148]

Answer:

The test is not significant at 5% level of significance, hence we conclude that there's no variation among the discussion sections.

Step-by-step explanation:

Assumptions:

1. The sampling from the different discussion sections was independent and random.

2. The populations are normal with means and constant variance

H_0: There's no variation among the discussion sections

H_1: There's variation among the discussion sections

\alpha =0.05

                Df     Sum Sq       Mean sq    F value     Pr(>F)

Section     7       525.01         75             1.87            0.99986

Residuals  189    7584.11        40.13

Test Statistic = F= \frac{75}{40.13} =1.87

Pr(>F) = 0.99986

Since our p-value is greater than our level of significance (0.05), we do not reject the null hypothesis and conclude that there's no significant variation among the eight discussion sections.

3 0
3 years ago
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