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devlian [24]
3 years ago
15

What is the y-intercept of y = 5?

Mathematics
2 answers:
yarga [219]3 years ago
7 0
The y intercept is 5 and the slope is a straight line
Leviafan [203]3 years ago
4 0

Answer:

The slope is a straight line and y-int is 5

Step-by-step explanation:

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How many solutions would y=-4x+11 and -6x+y=11 have?
likoan [24]

Answer:

1 solution

Step-by-step explanation:

There is only one solution as it is not a quadratic

4 0
3 years ago
For how many minutes did Lynn run at a greater speed than kael
dlinn [17]

Answer:

17

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
identify a pattern in the given list of numbers. then use this pattern to find the next number.​ 2,6,11,17,24,32
Sindrei [870]

Answer:

Next Number: 41

Step-by-step explanation:

The pattern is simply where the numbers go +1, +2, +3 and so on.

This can be applied in this sequence as we can se 2 --> 6 = +4

6 --> 11 = +5

11 --> 17 = +6

and so on...

Thus, we know this is the pattern and can simply add to 32.

24 --> 32 = +8, so the next is +9

32 + 9 = 41, and so, the next number in the sequence is 41 giving us our final answer.

3 0
3 years ago
James buys a shirt that is $22.95. He buys 3 pairs jeans. His total is $117.45. How much is each pair of jeans?
docker41 [41]
Ok so 117.45 is total then u subtract 117.45 by 22.95 equals 94.5 and u divide by 3 so u get 31.5 and add the unit rate so the answer is $31.50
4 0
4 years ago
Find area of the isosceles triangle formed by the vertex and the x-intercepts of parabola y=x2+4x−12.
xz_007 [3.2K]

The area of the isosceles triangle is 64 sq units.

<u>Solution:</u>

Part 1: x-intercepts

The x-intercepts occur at the points on the function where y=0

So, we need to solve

x^2-4x-12=0

The left side factors fairly easily into:

(x-6)(x+2)=0

So solution occur when

x-6=0\rightarrow x=6

and

x+2=0\rightarrow x=(-2)

So the x-intercepts are at (0,6) and (0,−2)

Part 2: vertex of the parabola

The vertex of a simple quadratic parabola occurs when the derivative of the quadratic is equal to 0.

The derivative of the given quadratic is

\frac{dy}{dx}=2x-4

By observation, this is equal to 0 when x=2

When x=2 the original equation becomes

y=(2)^2-4(2)-12

y=-16

Therefore the vertex of this parabola is at (2,−16)

The endpoints of the base of the isosceles triangle are (-6, 0) and (2, 0)

\Rightarrow so its base is 8

The height of the triangle reaches from the midpoint of the base (-2, 0) and the vertex (2, -16)

\Rightarrow so its height is 16

The area is  \frac{1}{2}\times \text { base }\times \text { height }=\frac{1}{2}\times8\times16=64 \text{ sq units }

6 0
3 years ago
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