The formula that is useful for solving both of these problems is ...

9. Given v₁=15, a=9.8, d=10, find v₂.
... (v₂)² = 15² + 2·9.8·10
... v₂ = √421 ≈ 20.5 . . . . m/s
10. Given d=12 m when a=-9.8 m/s² and v₂=0, find d when a=0.17·(-9.8 m/s²).
The formula tells us that d=(v₁)²/(2a), which is to say that the distance is inversely proportional to the acceleration. If acceleration is 0.17 times that on earth, distance will be 1/0.17 ≈ 5.88 times that on earth.
(12 m)/0.17 ≈ 70.6 m
Step-by-step explanation:
multiplication is the mathematical operation used with scale factor
Answer:
Yes; James got 76 answers correct
Step-by-step explanation:
Round 1: 50 x 0.8 = 40
Round 2: 40 x 0.75 = 30
Round 3: 30 x 0.2 = 6
40 + 30 + 6 = 76
Answer:
<h2>y=8</h2>
Step-by-step explanation:
4y-4=28
4y=28+4
4y=32
y=32/4
y=8
now plug in 8 for y and check the equation true:
4y-4=28
4*(8)-4=28
32-4=28
28=28
So, y is equal to eight 8