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2 years ago

Find the distance between points S(−2,4) and T(3,9). Round your answer to the nearest tenth.

Mathematics

1 answer:

Anarel [89]2 years ago

7 0

Answer:

distance between the points is also know as the "Slope"

To find that distance, you have to use the formula y2-y1/x2-x1

Therefore,

9-4/3--2

5/5, so the slope or the distance between the two points should be exactly 1

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Solve. −815x=2.24 Enter your answer as a mixed number in simplest form in the box. x =

lutik1710 [3]

x=2.7 x 10*-3

Step-by-step explanation:

-815x=2.24

x=-2.24/815

x=2.7 x 10*-3

3 0

3 years ago

Mathematics, Help, not sure about my answer on this one

olga nikolaevna [1]

Answer:

F. 2 1/9

Step-by-step explanation:

Step 1: Substitute q

$r = 3(\frac{1}{3^n} )+2$

When you plug in <em>n</em> = 1, 2, 3:

n(1) = 3

n(2) = 2.11111

n(3) = 2.3333

So our answer is F.

3 0

3 years ago

The area of a rectangular pool is 6992 m².

Nina [5.8K]

Step-by-step explanation:

area=6992m2

length=92m

Now,

area of rectangle=6992

3 0

3 years ago

Name the property the equation illustrates. 6(-6/2) = (-6/2)6

blondinia [14]

Inverse property of multiplication.

4 0

2 years ago

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A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by V = x2h

creativ13 [48]

It is given in the question that

A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by

$V = x^2h cm^3$

And the edge length of the base is 12 cm, the edge length of the base is decreasing at a rate of 2 cm/min, the height of the box is 6 cm, and the height is increasing at a rate of 1 cm/min.

Here we differentiate V with respect to t, and we use product rule, that is

$V = 2xh(dx/dt)+ x^2(dh/dt)$

Substituting the given values , we will get

$[tex]dV/dt = 2(12)(6)(-2)+ 12^2(1)$ [/tex]

$dV/dt = -288+144 = -144cm^3/min$

So at that moment, the volume is decreasing at the rate of

$144 cm^3/min$

4 0

2 years ago

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