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Slav-nsk [51]
3 years ago
8

Find the distance between points S(−2,4) and T(3,9). Round your answer to the nearest tenth.

Mathematics
1 answer:
Anarel [89]3 years ago
7 0

Answer:

1

distance between the points is also know as the "Slope"

To find that distance, you have to use the formula y2-y1/x2-x1

Therefore,

9-4/3--2

5/5, so the slope or the distance between the two points should be exactly 1

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Please answer this question
ICE Princess25 [194]

Answer:

A: 77

Step-by-step explanation:

360 - 109 - 137 - 37 = 77

3 0
2 years ago
1. Evaluate 7m + 3mn; when m=8 and n=14?
FrozenT [24]

Answer:

1. 392

2. 75

3. 12x^{2} - 5x -2

Step-by-step explanation:

1. 7×8 + 3×8×14 = 56 + 336 = 392

2. 675 ÷ (6 + 3) = 675 ÷ 9 = 75

3. 12x^{2} + 3x - 8x - 2 = 12x^{2} -5x-2

3 0
3 years ago
Plz help I will mark you brainlist plz ​
joja [24]

Answer:

m = 12.9g

v = 8cm3

d = ?

d = m/v

d = 12.9g/8cm3

D = 1.6125g/cm3

5 0
3 years ago
Belinda has a bag of beads. She uses 3 of the beads to make a bracelet and 5 of the beads to make a necklace. She uses 36 more b
Anastasy [175]
I just helped my sister on this problem its kinda scary... :P

If you mean 1/3 and 3/5

Belinda has 135 beads in total.

Find 1/3 of 135.

135 ÷ 3 = 45.

Belinda uses 45 beads to make the bracelet.

Hope I helped :)
7 0
3 years ago
A poll found that 53% of a sample of 1170 teens in a certain large country go online several times a day. (Treat this sample as
posledela

Answer:(a) margin error = 2.4%

(b) The margin error gives the measure in percentage of how the population parameter determined differ from the real population statistics or value.

(c) in 90% of the samples of teens in the country, the percent who go online several times a day will be within 50.6% and 55.4%. of the estimated 100%

Step-by-step explanation:

Using the proportion formulae

Margin error = z √p(1-p)/n

n= 1170, p = 53% = 0.53, 1-p = 0.47

and the z value at 90% C.I = 1.645

M error= 1.645 √0.53×0.47/1170

Margin error = 0.024 = 0.024 ×100

Margin error = 2.4%

53 - 2.4 = 50.6% and 53 + 2.4 = 55.4%

In other words 90% of the time: the number of teens who go online several time a day will be between 50.6 and 55.4%.

8 0
3 years ago
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