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Dima020 [189]
3 years ago
5

What's the temperature –15°F in degrees Celsius? EXPLAIN?

Mathematics
2 answers:
anzhelika [568]3 years ago
8 0

Answer: -26.1111 Degrees Celsius

Step-by-step explanation:

(F - 32) / 1.8 = C. This is the formula for it

(-15°F − 32) × 5/9 = -26.11°C

saul85 [17]3 years ago
4 0
-26.111 degrees Celsius
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Answer:

None of the above. (Ask your teacher to show you how to work this problem.)

Step-by-step explanation:

Since the results are identical, the matrix of the next three rolls will look exactly like this matrix. (A)

The matrix of all 6 rolls will look like a 6-row matrix with the bottom 3 rows identical to the top 3 rows.

Adding or multiplying A by a constant will not produce these results.

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You can replicate columns using matrix multiplication, so you can transpose A, multiply it by a suitable version of an identity matrix, then transpose the result:

((A^T)·[I | I ])^T will turn the 3-row matrix to a 6-row matrix where I is a 3x3 identity matrix. I've used [I | I] here to mean the 3x3 identity matrix is itself replicated horizontally to make a 6-column matrix. ^T indicates transpose.

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3 years ago
Find sin3A, cos<br> 3A and tan 3A when sin=1/2<br>​
Slav-nsk [51]

Answer:

Sin 3A = 1

cos 3A = 0

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Step-by-step explanation:

\sin A =  \frac{1}{2}  \\  \therefore \: \sin A =   \sin \: 30 \degree.. \bigg( \because \: \sin \: 30 \degree =  \frac{1}{2} \bigg) \\ \therefore \: A =   30 \degree \\  \\ now \\   \sin 3A =\sin (3 \times 30 \degree)= \sin \: 90 \degree = 1 \\  \\  \cos 3A =\cos (3 \times 30 \degree)= \cos \: 90 \degree = 0\\\\ \tan 3A =\tan (3 \times 30 \degree)= \tan \: 90 \degree =  \infty

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4 years ago
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The formula says
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R interest rate
T time

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The difference
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So the answer is d
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It is 134 is the answer
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