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Slav-nsk [51]
3 years ago
12

Explain how the mean, median, and mode affect your purchase decisions?

Mathematics
1 answer:
Goryan [66]3 years ago
4 0

Answer:

When a frequency distribution is symmetric, the mean, median and mode coincide in their value (X = Me = Mo). ... In a distribution skewed to the right, the relationship is reversed, the mode is greater than the median, and this in turn is greater than the mean (Mo> Me>).

Step-by-step explanation:

l hope and this can help you

You might be interested in
See attachment below
KatRina [158]

Answer: Third Option

x=1.469743

Step-by-step explanation:

We have the following exponential equation

3^{x+1}=15

We must solve the equation for the variable x

To clear the variable x apply the log_3 function on both sides of the equation

log_3(3^{x+1})=log_3(15)

Simplifying we get the following:

x+1=log_3(15)

To simplify the expression log_3 (15) we apply the base change property

log_b(y)=\frac{log(y)}{log(b)}

This means that:

log_3 (15)=\frac{log(15)}{log(3)}

Then:

x+1=\frac{log(15)}{log(3)}

x=\frac{log(15)}{log(3)}-1

x=1.469743

6 0
3 years ago
One more time what 4 + 4 × 4 + 4 ÷ 4=
katrin [286]

Answer:

should be 21

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Solve each proportion t/9=35/6
kotegsom [21]
The answer to the proportion is t=52.5
8 0
3 years ago
Please help is urgent
vazorg [7]

Answer:

x ≈ 7.2

Step-by-step explanation:

Given a tangent- secant from an external point to the circle, then

the the square of the measure of the tangent is equal to the product of the external part of the secant and the entire secant, that is

x² = 4(4 + 9) = 4 × 13 = 52 ( take the square root of both sides )

x = \sqrt{52} ≈ 7.2 ( to the nearest tenth )

5 0
3 years ago
Machine A produces 100 parts twice as fast as Machine B does. Machine B produces 100 parts in 40 minutes. If each machine produc
umka2103 [35]

Answer:

30 parts

Step-by-step explanation:

We are given that machine produces 100 parts twice as  fast as machine B does.

Machine produces 100 parts in 40 minutes.

We have to find number of parts produces by machine A in 6 minutes.

According to question

Machine A  takes time to produce 100 parts =\frac{40}{2}=20 minutes

Machine A and machine B produces parts at constant rate.

Machine A produces parts at the rate=\frac{100}{20}=5 parts /minute

In one minute,Machine A produces =5 parts

In 6 minutes , machine B produces =5\times 6=30 parts

Hence, machine A produce parts in 6 minutes=30

8 0
3 years ago
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