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3 years ago

12

Explain how the mean, median, and mode affect your purchase decisions?

1 answer:

Goryan [66]3 years ago

4 0

Answer:

When a frequency distribution is symmetric, the mean, median and mode coincide in their value (X = Me = Mo). ... In a distribution skewed to the right, the relationship is reversed, the mode is greater than the median, and this in turn is greater than the mean (Mo> Me>).

Step-by-step explanation:

l hope and this can help you

You might be interested in

See attachment below

KatRina [158]

Answer: Third Option

$x=1.469743$

Step-by-step explanation:

We have the following exponential equation

$3^{x+1}=15$

We must solve the equation for the variable x

To clear the variable x apply the $log_3$ function on both sides of the equation

$log_3(3^{x+1})=log_3(15)$

Simplifying we get the following:

$x+1=log_3(15)$

To simplify the expression $log_3 (15)$ we apply the base change property

$log_b(y)=\frac{log(y)}{log(b)}$

This means that:

$log_3 (15)=\frac{log(15)}{log(3)}$

Then:

$x+1=\frac{log(15)}{log(3)}$

$x=\frac{log(15)}{log(3)}-1$

$x=1.469743$

6 0

3 years ago

One more time what 4 + 4 × 4 + 4 ÷ 4=

katrin [286]

Answer:

should be 21

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Solve each proportion t/9=35/6

kotegsom [21]

The answer to the proportion is t=52.5

8 0

3 years ago

Please help is urgent

vazorg [7]

Answer:

x ≈ 7.2

Step-by-step explanation:

Given a tangent- secant from an external point to the circle, then

the the square of the measure of the tangent is equal to the product of the external part of the secant and the entire secant, that is

x² = 4(4 + 9) = 4 × 13 = 52 ( take the square root of both sides )

x = $\sqrt{52}$ ≈ 7.2 ( to the nearest tenth )

5 0

3 years ago

Machine A produces 100 parts twice as fast as Machine B does. Machine B produces 100 parts in 40 minutes. If each machine produc

umka2103 [35]

Answer:

30 parts

Step-by-step explanation:

We are given that machine produces 100 parts twice as fast as machine B does.

Machine produces 100 parts in 40 minutes.

We have to find number of parts produces by machine A in 6 minutes.

According to question

Machine A takes time to produce 100 parts = $\frac{40}{2}=20 minutes$

Machine A and machine B produces parts at constant rate.

Machine A produces parts at the rate= $\frac{100}{20}=5 parts /minute$

In one minute,Machine A produces =5 parts

In 6 minutes , machine B produces = $5\times 6=30$ parts

Hence, machine A produce parts in 6 minutes=30

8 0

3 years ago