Question

A random sample of n 5 4 individuals is selected from a population with m 5 35, and a treatment is administered to each individual in the sample. After treatment, the sample mean is found to be M 5 40.1 with SS 5 48. a. How much difference is there between the mean for the treated sample and the mean for the original population

Answer 1

Answer:

5.1

Step-by-step explanation:

Given that:

sample size n = 4

the mean of the original population  μ is = 35

and the mean for the sample after treatment M is = 40.1

standard deviation of the sample SS = 48

The difference between the mean for the treated sample and the mean for the original population is therefore calculated as: M -  μ

= 40.1 - 35

= 5.1

The standard error of M is = $\dfrac{standard \ deviation \ of \ the \ sample}{\sqrt{sample \ size} }$

The standard error of M is = $\dfrac{SS}{\sqrt{n} }$

The standard error of M is = $\dfrac{48}{\sqrt{4} }$

The standard error of M is = $\dfrac{48}{2 }$

The standard error of M is = 24