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solniwko [45]
3 years ago
14

Jim earns a regular hourly rate of $5 and a premium hourly rate of $6. He worked 45 hours last week. What is his gross pay?

Mathematics
1 answer:
Troyanec [42]3 years ago
8 0
Is 495 just multiply 5 by 45 and then sum 6 by 45
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Solve For X <br> A 3 <br> B 30<br> C 60<br> D 90
Anarel [89]

Answer:

sln

10x+10x+30+90=180

20x+120=180

20x=180-120

20x=60

x=3

the answer is A) 3

8 0
3 years ago
Suppose you have an experiment where you flip a coin three times. You then count the number of heads. a.) State the random varia
coldgirl [10]

Answer:

The answer to each point is below

Step-by-step explanation:

We will solve point by point:

a)  We have to:

Random variable X = number of heads

Let, H => heads, T => tails

b) We have that the combinations are

TTT, TTH, THT, THH, HTT, HTH, HHT, HHH

Number of Heads (X)  0     1      2     3

Probability (P)             1/8   3/8  3/8   1/8

c) attached the histogram.

d)  We have the following:

Mean = E (X) = 0 * 1/8 + 1 * 3/8 + 2 * 3/8 + 3 * 1/8

m = 1.5

The mean is 1.5

e) E (X ^ 2) = 0 * 1/8 + 12 * 3/8 + 22 * 3/8 + 32 * 1/8 = 3

Variance = E (X ^ 2) - (E (X)) ^ 2

Var = 3 - (1.5) ^ 2

Var = 0.75

The variance is 0.75

f) standard deviation = (Var) ^ (1/2) = (0.75) ^ (1/2) = 0.866

sd = 0.866

the standard deviation is 0.866

g) P (2 or more heads) = 3/8 + 1/8 = 0.5

The probability is 50%

h)  P (two heads) = 3/8 = 0.375

It is likely that out of 8 times of 3 flips, 3 times we can observe two heads out of 3, therefore it is not unusual.

6 0
3 years ago
Solve for a:<br><br> 28000/1+a = 0
nika2105 [10]

1207838929299236636236+2892

5 0
3 years ago
There are 7 7/8 cups of skittles in a Jar. If 2 1/4 cups are used for a party, how many skittes are left in the jar?
maw [93]
2 1/4 = 2 2/8. So, simply subtract 7 7/8 - 2 2/8 to get your final answer of 5 5/8
4 0
3 years ago
What is not a problem modular division is used for?
Oksana_A [137]

Answer:

First let's define what modular arithmetic is, what would come is an arithmetic system for equivalence classes of whole numbers called congruence classes.

Now, the modular division is the division in modular arithmetic.

Answering the question, a modular division problem like ordinary arithmetic is not used, division by 0 is undefined. For example, 6/0 is not allowed. In modular arithmetic, not only 6/0 is not allowed, but 6/12 under module 6 is also not allowed. The reason is that 12 is congruent with 0 when the module is 6.

4 0
3 years ago
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