Answer:
Please see attached graph.
Step-by-step explanation:
The equations for straight lines are given as:
i) y = x +4
ii) y= x-4
Yon can form a table for values of x and y that are true for an equation and use these values as coordinates ( x,y ) to plot the graphs and view the lines to select the correct labels for the equations.
For i)
y= x+4
x y coordinates
-3 1 (-3,1 )
-2 2 (-2,2)
-1 3 (-1,3)
0 4 ( 0,4)
1 5 ( 1,5)
2 6 ( 2,6)
3 7 ( 3,7)
Plot the points on a graph tool and draw the line. Do the same for the second equation to view both graphs as shown in the attached graph.
The answer is 7 R 4! hoped this helps!
:Jason is tossing a fair coin. He tosses the coin ten times and it lands on heads eight times. If Jason tosses the coin an eleventh time, what is the probability that it will land on heads?
Solution:
The probability would be ½. The result of the eleventh toss does not depend on the previous
results.
we have
Let's Isolate the variable y in each of the cases and then compare with Fiona's equation to determine the solution of the problem
case A) 
Multiply by 
both sides
Divide by 
both sides
therefore
the case A) is not equal to Fiona's equation
case B) 
Multiply by both sides
Divide by 
both sides
therefore
the case B) is not equal to Fiona's equation
case C) 
Multiply by both sides
Divide by both sides
therefore
the case C) is not equal to Fiona's equation
case D) 
Multiply by 
both sides
Divide by both sides
therefore
the case D) is equal to Fiona's equation
<u>the answer is</u>
Answer:
Krishna's marks x marks
so...
xˉ=15
xˉ=15n=10
xˉ=15n=10∑x=x+x−8+x−6+x−3+x−1+x+x+2+x+3+x+4+x+6=10x−3
15=10x-3/10
150+3=10x
x=150/10=15.3 marks
<em><u>Krishna scored 15.3 marks.</u></em>
<em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>helps</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em><em><u>sis</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
