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iVinArrow [24]
3 years ago
9

Solve for x 4(2x-1)= 3x-19

Mathematics
2 answers:
Sophie [7]3 years ago
8 0
X=-3
This is the answer
drek231 [11]3 years ago
7 0

Answer:

x = -3

Step-by-step explanation:

In an equation our aim is to find the value of what we are looking for as well as keeping the equation balanced. For example if we took away 4 only from one side then the equation would change so it's an important rule to keep in mind when solving equations, that you need to keep both sides of the equation the same.

4 ( 2x - 1 ) = 3x - 19

→ Expand the brackets

8x - 4 = 3x - 19

→ Minus 3x from both sides to isolate -19 and bring all the x coefficients to one side

5x - 4 = -19

→ Add -4 to both sides to isolate 5x

5x = -15

→ Divide both sides by 5 to isolate x and therefore find the value of x

x = -3

→ We can substitute x = -3 back into 4 ( 2x - 1 ) = 3x - 19 to see if we have the correct solution, if we end with the same number on both sides then  x = -3 is correct.

4 ( 2x - 1 ) = 3x - 19

8x - 4 = 3x - 19

( 8 × -3 ) - 4 = ( 3 × -3 ) - 19

-24 - 4 = - 9 - 19

-28 = -28

So x = -3 is correct

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(Will give Brainliest/5 Stars if correct answer)
tensa zangetsu [6.8K]
Answer: Choice D) 
The angle between the two vectors is approximately 71.6 degrees

----------------------------------------------
----------------------------------------------

Work Shown: 

Each time I write the word "dot" I mean "dot product". 

|u| = length of vector u
|u| = sqrt(u dot u)
|u| = sqrt(<8,4> dot <8,4>)
|u| = sqrt(8*8 + 4*4)
|u| = sqrt(64 + 16)
|u| = sqrt(80)
|u| = sqrt(16*5)
|u| = sqrt(16)*sqrt(5)
|u| = 4*sqrt(5)

-----------------------

|v| = length of vector v
|v| = sqrt(v dot v)
|v| = sqrt(<9,-9> dot <9,-9>)
|v| = sqrt(9*9 + (-9)*(-9))
|v| = sqrt(81+81)
|v| = sqrt(2*81)
|v| = sqrt(2)*sqrt(81)
|v| = sqrt(2)*9
|v| = 9*sqrt(2)

-----------------------

u dot v = <8,4> dot <9,-9>
u dot v = 8*9 + 4*(-9)
u dot v = 72-36
u dot v = 36

-----------------------

cos(theta) = (u dot v)/(|u|*|v|)
cos(theta) = (36)/(4*sqrt(5)*9*sqrt(2))
cos(theta) = (36)/(36*sqrt(10))
cos(theta) = 1/(sqrt(10))
cos(theta) = sqrt(10)/10
theta = arccos(sqrt(10)/10)
theta = 71.56505
which rounds to 71.6 when rounding to one decimal place (nearest tenth)

That's why the approximate answer is roughly 71.6 degrees

7 0
3 years ago
1/7+2 1/8-3/2=? <br> What is the first step
Sauron [17]

According to (P)arenthesis (E)xponets (M)ultiply (D)ivide (A)dd (S)ubtract, it would be (1 / 7).


4 0
3 years ago
Can someone pls help me solve thiss
Nikolay [14]

Answer:

The value of x = 9

Step-by-step explanation:

Given the angles of the triangle

  • (13x+2)°
  • (5x-7)°
  • (3x-4)°

We know that the sum of angles of a triangle is 180°.

Therefore,

(13x+2)° + (5x-7)° + (3x-4)° = 180°

13x+2 + 5x-7 + 3x-4 = 180°

21x + 2 - 11 = 180°

21x - 9 = 180°

21x = 180° + 9

21x = 189

divide both side sby 21

21x/21 = 189/21

x = 9

Therefore, the value of x = 9

3 0
3 years ago
The size of a TV is measured by its diagonal. You want to buy a TV that has a 32
ANEK [815]

The width of the TV is 27.9 inches

Step-by-step explanation:

Given,

Diagonal of TV = 32 inch

Height of TV = 15.7 inch

The diagonal makes the TV into a right triangle,

Therefore,

Diagonal = hypotenuse = c = 32 inch

Height = perpendicular = a = 15.7 inch

Width = base = b

Using pythagoras theorem

a^2+b^2=c^2\\(15.7)^2+b^2=(32)^2\\246.49+b^2=1024\\b^2=1024-246.49\\b^2=777.51

Taking square root on both sides

\sqrt{b^2}=\sqrt{777.51}\\b=27.88

Rounding off to nearest tenth

b = 27.9 inches

The width of the TV is 27.9 inches

Keywords: Pythagoras theorem, square root

Learn more about square root at:

  • brainly.com/question/2154850
  • brainly.com/question/2367554

#LearnwithBrainly

7 0
3 years ago
If A:B=1/2:1/3, and B:C is 1/2:1/3, what is A:B:C?
Leya [2.2K]

Answer:

Step-by-step explanation:

C)3:2:6

6 0
3 years ago
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