Question

The size of a TV is measured by its diagonal. You want to buy a TV that has a 32

Answer 1

The width of the TV is 27.9 inches

Step-by-step explanation:

Given,

Diagonal of TV = 32 inch

Height of TV = 15.7 inch

The diagonal makes the TV into a right triangle,

Therefore,

Diagonal = hypotenuse = c = 32 inch

Height = perpendicular = a = 15.7 inch

Width = base = b

Using pythagoras theorem

$a^2+b^2=c^2\\(15.7)^2+b^2=(32)^2\\246.49+b^2=1024\\b^2=1024-246.49\\b^2=777.51$

Taking square root on both sides

$\sqrt{b^2}=\sqrt{777.51}\\b=27.88$

Rounding off to nearest tenth

b = 27.9 inches

The width of the TV is 27.9 inches

Keywords: Pythagoras theorem, square root

Learn more about square root at:

• brainly.com/question/2154850
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