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3 years ago

Triangle P Q R is shown. Angle Q P R is a right angle. The length of hypotenuse Q R is 14.1 and the length of P R is 12.7.

Mathematics

2 answers:

Shkiper50 [21]3 years ago

6 0

Answer:

The correct option is option (c).

Sin \ P= \frac {RQ}{PQ}

Step-by-step explanation:

Nadusha1986 [10]3 years ago

3 0

Answer:

∠ R ≈ 26°

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos R = $\frac{adjacent}{hypotenuse}$ = $\frac{PR}{QR}$ = $\frac{12.7}{14.1}$ , thus

R = $cos^{-1}$ ( $\frac{12.7}{14.1}$ ) ≈ 26° ( to the nearest degree )

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Recall that in the problem involving compound interest, the balance A for P dollars invested at rate r for t years compounded n

RoseWind [281]

Answer:

(a)∴A=$6753.71.

(b)∴A=$1480.24

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Step-by-step explanation:

We use the following formula

$A=P(1+\frac rn)^{nt}$

A=amount in dollar

P=principal

r=rate of interest

(a)

P=$2,500, r=5%=0.05,t =20 years , n= 4

$A=\$2500(1+\frac{0.05}{4})^{(20\times 4)$

=$6753.71

∴A=$6753.71.

(b)

P=$1,000, r=8% =0.08,t =5 years , n= 2

$A=\$1000(1+\frac{0.08}{2})^{(5\times 2)$

=$1480.24

∴A=$1480.24

(c)

A=$10,000, r=6% =0.06,t =5 years , n= 4

$10000=P(1+\frac{0.06}{4})^{(5\times 4)}$

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$\Rightarrow P=7424.70$

∴P=$7424.70

(d)

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$100000=P(1+\frac{0.07}{12})^{(10\times 12)}$

$\Rightarrow P=\frac{100000}{(1+\frac{0.07}{12})^{120}}$

$\Rightarrow P=49759.62$

∴P=$49759.62

(e)

A=$100,000, r=10% =0.10,t =30 years , n= 12

$100000=P(1+\frac{0.10}{12})^{(30\times 12)}$

$\Rightarrow P=\frac{100000}{(1+\frac{0.10}{12})^{360}}$

$\Rightarrow P=5040.99$

∴P=$5040.99

(f)

A=$100,000, r=7% =0.07,t =20 years , n= 4

$100000=P(1+\frac{0.07}{4})^{(20\times 4)}$

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3 years ago

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tresset_1 [31]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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