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dimulka [17.4K]

3 years ago

11

I need help with this geometry math assignment I been struggling and I need help on it very fast and it is due today so please h

elp me out I will mark you Brainly and I’m stress and worry.Also please help me I need the answer I try my best

1 answer:

deff fn [24]3 years ago

4 0

Answer:

One tip: Do the top first

Step-by-step explanation:

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

ddd [48]

Answer:

$f'(x) = 4x^2 - 3$ for $x \le -3$

Step-by-step explanation:

See attachment for proper question

Given

$f(x) = -\frac{1}{2}\sqrt{x + 3}$

For

$x \ge -3$

Required

Determine the inverse function

$f(x) = -\frac{1}{2}\sqrt{x + 3}$

Replace f(x) with y

$y = -\frac{1}{2}\sqrt{x + 3}$

Swap the positions of x and y

$x = -\frac{1}{2}\sqrt{y + 3}$

Multiply both sides by -2

$-2 * x =-2 * -\frac{1}{2}\sqrt{y + 3}$

$-2x =\sqrt{y + 3}$

Square both sides

$(-2x)^2 =(\sqrt{y + 3})^2$

$4x^2 =y + 3$

Make y the subject

$y = 4x^2 - 3$

The inverse has been solved. So, we need to replace y with f'(x)

$f'(x) = 4x^2 - 3$

Next, is to determine the interval

$x \ge -3$

Change inequality to $\le$

$x \le -3$

Hence, the inverse function is:

$f'(x) = 4x^2 - 3$ for $x \le -3$

7 0

3 years ago

Jammal makes a cut through a block of florist's foam, as shown. What are the dimensions of the exposed cross section?

Ahat [919]

Answer:

C. 3 in x 6 in

Step-by-step explanation:

Jammal cuts the block in a straight line parallel to one side... so the section revealed when he finishes his cut will be identical as the parallel side to which the cut is done.

We know the the left side of the prism on the image is 3 inches wide and 6 inches high... so that will also be the dimensions of the exposed cross section.

The answer is then 3 inches y 6 inches. The thickness of the block (5 inches) has no impact on the exposed area of the cross-section.

8 0

4 years ago

Given that 2^x = 7, find the value of 4^x-1.

Helga [31]

$4=2^2\\\\4^x=(2^2)^x=(2^x)^2=7^2=49\\\\4^x-1=49-1=48$

$If\ is\ 4^{x-1},\ then\\\\4^{x-1}=\dfrac{4^x}{4}=\dfrac{49}{4}=12\frac{1}{4}$

$Used:\\\dfrac{a^n}{a^m}=a^{n-m}$

4 0

3 years ago

The diameter of a quarter is 24.26 mm. Find the area

Vinil7 [7]

R=12.13
A=pi×r²
A=pi×12.13²
A≈462.2442041
A≈462.2 (to the nearest tenth).

So the answer is A≈462.2.

6 0

3 years ago

CALLING ON K12 STUDENTS... I'm in Honors Geometry and am so stuck on the end of the year Trig in Baseball assignment... Anybody

Katyanochek1 [597]

RIP, i finished my geometry hon. EOC today, i'm in 8th :P

7 0

3 years ago