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vredina [299]
3 years ago
12

A math teacher claims that she has developed a review course that increases the scores of students on the math portion of a coll

ege entrance exam. Based on data from the administrator of the​ exam, scores are normally distributed with mu equalsμ=522522. The teacher obtains a random sample of 20002000 ​students, puts them through the review​ class, and finds that the mean math score of the 20002000 students is 527527 with a standard deviation of 110110. Complete parts​ (a) through​ (d) below. ​(a) State the null and alternative hypotheses. Let muμ be the mean score. Choose the correct answer below. A. Upper H 0 : mu equals 522H0: μ=522​, Upper H 1 : mu not equals 522H1: μ≠522 B. Upper H 0 : mu less than 522H0: μ<522​, Upper H 1 : mu greater than 522H1: μ>522 C. Upper H 0 : mu greater than 522H0: μ>522​, Upper H 1 : mu not equals 522H1: μ≠522 D. Upper H 0 : mu equals 522H0: μ=522​, Upper H 1 : mu greater than 522
Mathematics
1 answer:
xxMikexx [17]3 years ago
8 0

Answer: D

H0: μ=522

H1: μ>522

Step-by-step explanation:

The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.

So, for this case;

The null hypothesis is that the mean score equals to 522

H0: μ=522

The alternative hypothesis is that the mean score is greater than 522.

H1: μ>522

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the ratio of girls to boys in the math club was 3.5. if there were 120 children altogether, how many girls were there?
sergejj [24]

3 girls to 5 boys

3+5 =8

120/8 = 15

3 *15 = 45 girls


5 0
3 years ago
Please help answer <br> Will give Brainlst
Artyom0805 [142]

Answer:

x= -3

y= -5

Step-by-step explanation:

10y - 3x = -41

+

-5y + 3x = 16

10y + (-5y) = 5y

-3x + 3x = 0

-41 + 16 = -25

5y + 0 = -25

y = -25/5

y= -5

10y -3× = -41

(10×-5) - 3x = -41

- 3x = - 41 + 50

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4 0
3 years ago
Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal
Usimov [2.4K]

Answer:

a) We have that the significance is given by \alpha =0.01 and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case z_{crit}=2.33

So then the rejection region would be z>2.33

b) We have that the significance is given by \alpha =0.05, \alpha/2 =0.025 and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case z_{crit}=\pm 1.96

So then the rejection region would be z>1.96 \cup z

Step-by-step explanation:

Part a

We have that the significance is given by \alpha =0.01 and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case z_{crit}=2.33

So then the rejection region would be z>2.33

Part b

We have that the significance is given by \alpha =0.05, \alpha/2 =0.025 and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case z_{crit}=\pm 1.96

So then the rejection region would be z>1.96 \cup z

7 0
3 years ago
A Salesman worked on a weekly salary of $180.00 . To this was added a commission of 5% on all sales over $500. It his sales for
Anvisha [2.4K]
250x.05 = 12.5 + 180 = 192.50
4 0
3 years ago
Enter the unknown value that makes this statement true: ___% of 540 is 180
seropon [69]

Answer:

33.3

Step-by-step explanation:

3 0
2 years ago
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