It will depend on how many feet are in 162 inches.
<h3>Inch-to-feet conversion</h3>
According to metrics, 12 inches = 1 foot
Hence, 162 inches will be: 162/12 = 13.5 ft
However, the maximum height that the bridge can accommodate according to the illustration is 12 ft 5 inches.
13.5 ft is significantly more than 12 ft 5 inches.
Thus, it is highly unlikely that the truck can pass safely under the bridge.
More on metric conversion can be found here: brainly.com/question/10943201
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Answer:
Affirmative action programs for under-represented minorities.
Explanation:
Affirmative action is defied as a policy where the race, color, sex, national origin or religion are considered to increase the opportunities provided to an underrepresented section of the society. It supports members of any disadvantage group or minorities who have discriminated in areas of housing, employment and education.
In the context, The University of California took the affirmative actions against the disadvantaged minorities to provide admission to them despite the Federal court decision in California v. Bakke (1978) to prohibit the use of the quota system to get admission in the university.
Answer:
Demographic variables
Explanation:
A series of advertisements are released by the State of Alabama Tourism Board featuring traditional families experiencing various state attraction. Since the apparent goal of these advertising is traditional family, the State of Alabama Tourism Board seems to have segmented the market utilizing demographic variables
As significant factors of the income distribution, demographic variables are sometimes listed. The following sections address the impact of 3 demographic variables on income distribution: (a) age structure; (b) marriage and composition of the family; and (c) income group differential fertility.
Answer:
Explanation:
An underlying cause was the growing racial tension in a rapidly-changing city and economy, with competition for jobs, housing, and political power. The violence did not end until after Governor Joseph M.