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OLga [1]
3 years ago
12

Please help me now plz I will mark you brainliest

Mathematics
1 answer:
Alja [10]3 years ago
7 0

Answer:

x=4\sqrt{3}

Step-by-step explanation:

Use cosine ratio.

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Line MN passes through points M(4, 3) and N(7, 12). If the equation of the line is written in slope-intercept form, y = mx + b,
nataly862011 [7]

Answer:

b = -9.

Step-by-step explanation:

The line passes through (4, 3) and (7, 12). First, we need to find the slope: the rise over the run.

(12 - 3) / (7 - 4) = 9 / 3 = 3.

Now that we have the slope, we can say that m = 3. So, we have an equation of y = 3x + b. To find b, we can use M(4, 3) and say that y = 3 and x = 4.

3 = 3 * 4 + b

b + 12 = 3

b = -9.

Hope this helps!

4 0
3 years ago
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Vicky did a survey to answer the following question: What is the average fitness score of grade 8 students? The mean fitness sco
mario62 [17]
The mean is calculated by adding up all of the data points and then dividing the sum by the amount of points added.

The mean fitness score was 3.2 points.  If all of the students scored the same thing (3.2 points) then this would be the fitness score of each student.

Thus, the answer is D. 3.2 points.
3 0
3 years ago
Which is the area of a square with one side that measures 1 foot?
castortr0y [4]
None of the above so D
3 0
3 years ago
Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays
katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

<u>Answer:</u> The half life of the sample of phosphorus-32 is 14.28days^{-1}

<u>Step-by-step explanation:</u>

The equation used to calculate the half life of the sample is given as:

m(t)=m_o(1/2)^{t/h}

where,

m(t) =  amount of sample after time 't' = 356 g

m_o = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}

Hence, the half life of the sample of phosphorus-32 is 14.28days^{-1}

7 0
4 years ago
How can the Subtraction Property of Equality be used to solve addition equations?
IrinaVladis [17]
To keep the balance, add 5 to each side. Example 2. Solve<span> the </span>equation<span> -8 = n - (-4). Solution: After simplifying the right side of the</span>equation<span>, use the </span>subtraction property of equality<span> to </span>subtract<span> 4 from both sides of the</span><span>equation
</span>
8 0
3 years ago
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