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AlexFokin [52]
3 years ago
12

Help plzzzzzzzzzzzzzzzzzzzzz

Mathematics
1 answer:
Klio2033 [76]3 years ago
6 0
The human ran 0.45 miles per minute.

27 divided by 60 = 0.45

The 60 is the number of seconds in a minute.

Hope this helped! :)
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Find the product mentally.<br> 1/4x32
julsineya [31]
I’m not sure but I think 8
4 0
4 years ago
Read 2 more answers
Factor by grouping.<br> 8y2 + y + 40y + 5
Harman [31]
Answer: (8y+1)(y+5)

Step by step:
8y2 + y +40y + 5
y(8y+1) + 5(8y+1)
(8y+1)(y+5)
3 0
3 years ago
Each month, an American household generates an average of 28 pounds of newspaper for garbage or recycling. Assume the standard d
Annette [7]

a) For x = 27:

z = 27-28/2 = -0.5

For x = 31:

z = 31-38/2 = 1.5

From the normal distribution table, P(27 < x < 31) = P(-0.5 < z < 1.5) = P(z < 1.5) - P(z < -0.5) = 0.9332 - 0.3085 = 62.47%

b)  For x > 30.2:

z = 30.2-28/2 = 1.1

From the normal distribution table, P(x > 30.2) = P(z > 1.1) = 1 - P(z > 1.1) = 1 - 0.8643 = 13.57%

4 0
2 years ago
The bed of a truck is stacked with with boxes of paper. The boxes are stacked 5 boxes deep by 4 boxes high by 4 boxes across
marysya [2.9K]

Answer:

3

Step-by-step explanation:

The boxes are stacked 5 boxes deep by 4 boxes high by 4 boxes across, then there are 5\cdot 4\cdot 4=80 boxes in total.

The mass of 1 box of paper is 22.5 kilograms, so 80 boxes weigh 22.5\cdot 80=1800 kilograms.

When the driver is in the truck, the mass is 2948.35 kilograms, then the total mass is

2948.35+1800=4748.35\ kg.

Let n be the number of boxes of paper the driver must deliver at the first stop. Their weigth is 22.5n kg and the weight of the truck without n boxes is

4748.35-22.5n\ kg.

Trucks with a mass greater than 4700 kilograms are not allowed over the bridge, thus

4748.35-22.5n48.35,\\ \\n>\dfrac{967}{450}=2\dfrac{67}{450}.

Hence, the driver must deliver at least 3 boxes at the first shop.

8 0
3 years ago
I can't figure out the equivalent fraction. Whoever gets it first gets brainliest, and please do explaination
cupoosta [38]

Factorize the numerator and denominator. You'll see that they both have a factor of 4 that can be canceled. The introduce a factor of 3 to change the denominator to 36.

\dfrac{28}{48} = \dfrac{4\times7}{4\times12} = \dfrac7{12} = \dfrac{3\times7}{3\times12} = \boxed{\dfrac{21}{36}}

6 0
2 years ago
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